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10/18/2013 - Missed Opportunity


  • 23 months ago · Quote · #101

    patrickpeng168

    wouldn't Rxf6 work too?

  • 23 months ago · Quote · #102

    patrickpeng168

    awesome, KINGS LANDING

  • 23 months ago · Quote · #103

    Airin10

    [COMMENT DELETED]
  • 23 months ago · Quote · #104

    Airin10

    Could be the white peaces beat black ones in two white movements?..

    I mean .. Txf6 .. f6xT .. Qg7+ ??

  • 23 months ago · Quote · #105

    smarques

    Embarassed

  • 23 months ago · Quote · #106

    person1313

    pg. 6 0r 7

  • 23 months ago · Quote · #107

    im_joe

    unravels nicely

  • 23 months ago · Quote · #108

    victorpu

  • 23 months ago · Quote · #109

    victorpu

  • 23 months ago · Quote · #110

    aquinojsv10

    Solved! =]

  • 23 months ago · Quote · #111

    amt976

    Nice 5. Qf7? Why not?

  • 23 months ago · Quote · #112

    MDCCP

    Cool :) !

  • 23 months ago · Quote · #113

    victorpu

  • 23 months ago · Quote · #114

    africar

    dkcoollike wrote:

    Hi adriancook, mammoth

     

    What about 5. Qf7 ???

    I think 5 Qf7 is better. With 5 Qf7 we have mate in 8 moves. In the "solution", we have mate in 9.

  • 23 months ago · Quote · #115

    woefulknignt

    Stupid puzzle...not me being sour grapes...it just lacks discipline. Enjoy the weekend all and CHESS ON!

  • 23 months ago · Quote · #116

    BryanCFB

    massung wrote:
    Kings_Landing wrote:
    [Puzzles snipped]

    I believe the second puzzle is wrong. There's actually a forced mate in 3 that doesn't give black an opportunity to move: 1. Ra5+ Kxa5 2. Qc5+ Ka6 3. Qb6#.

    The solution (as-shown) seems flawed to me; there's nothing forcing black to take the rook with the bishop. In fact, Rd3+ or Rg6+ starts giving black time (and options), meaning the solution - as shown - is not a mate in 2.

    Am I missing something?

    If 1...Rd3+ then 2. Bd5#.  If 1...Rg6+ then 2. Be6#.  In each case, white blocks the rook check from black with a discovered check, and each of the two black checks prevent black from capturing 2...Bxb1, due to interference on the h7-b1 diagonal.

  • 23 months ago · Quote · #117

    victorpu

    victorpu wrote:

    Solved! =]

  • 23 months ago · Quote · #118

    victorpu

    Bryan681972 wrote:
    massung wrote:
    Kings_Landing wrote:
    [Puzzles snipped]

    I believe the second puzzle is wrong. There's actually a forced mate in 3 that doesn't give black an opportunity to move: 1. Ra5+ Kxa5 2. Qc5+ Ka6 3. Qb6#.

    The solution (as-shown) seems flawed to me; there's nothing forcing black to take the rook with the bishop. In fact, Rd3+ or Rg6+ starts giving black time (and options), meaning the solution - as shown - is not a mate in 2.

    Am I missing something?

    If 1...Rd3+ then 2. Bd5#.  If 1...Rg6+ then 2. Be6#.  In each case, white blocks the rook check from black with a discovered check, and each of the two black checks prevent black from capturing 2...Bxb1, due to interference on the h7-b1 diagonal.

  • 23 months ago · Quote · #119

    BryanCFB

    eaglewatch88 wrote:
    Kings_Landing wrote:
     

    Hallo "kings_Landing" : nice puzzles , in your second puzzle after white played kd6 , what if black plays kb6 instead of Bxb1. Is still a mate in 2 possible??

    Yes.  2. Bc2# because it is a discovered check, and 2...Bxb1 is prevented.

  • 23 months ago · Quote · #120

    BryanCFB

    africar wrote:
    dkcoollike wrote:

    Hi adriancook, mammoth

     

    What about 5. Qf7 ???

    I think 5 Qf7 is better. With 5 Qf7 we have mate in 8 moves. In the "solution", we have mate in 9.

    Actually 5. Qxf7+ leads to mate in nine while 5. Rxf7 (solution) leads to mate in eight.  Check BenTal post #90 which nicely shows these two lines as well as 5. Bxf7+ (also mate in nine).


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