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easy to fall into the stalemate trap with Rxh7 instead of d7+. A good lesson to always be on the look out for an accidental stalemate.
Good to solve.It has also another many many way......................
You almost expected it to be an exclusively Queening problem. ie. converting a pawn to a Queen. But they stopped us just short of the promotion.
This may not be efficient . . . but at least you get to promote two pawns
thanks for your way not to promote a pawn with Q,and someones correct method,was able to solve,rule of thumb,lesson from bill indirectly,thanks1,Kc6...Rh7,2.pd7+...Rd73.Rh8,as far as puzzle went but to mate.3.Rh8...Rd8,4. Rd8#
Il faut savoir donner pour assurer le gain... bonne journée.
I've played several endgames like this. Two interesting checkmates - One with two pawns and one with a king and a rook (with a pawn for protection). Saw it right away.
Damn easy problem. Black is trying for a draw. Don't take the rook it would be stalemate.
would K move to Kb7,Kd7,on second move,he has a choice,or would Kd7 leed to # quicker,or stop pawn promotion?
Shows the power of pawns. I must be getting a bit better, I saw this one.
There are many ways to win this position [as far as I can see, any move of the rook on the 6th rank will do it, maybe even any move ]. 1. Kc6 is only the most efficient manner.
After a closer look, it really looks like even 1. d7? is clinching it.
nice stratogy,but how many people would have solved your way.mate in 4 is alot more efficient
@ paulified22: I just tried to show that even the worst move in the position (1.d7????) is winning. And by the way, I really wonder how many people found the mate in 4 directly. I first found 1.Rg6 as a winning option. Since "my" move was not accepted, I tried harder and only then found 1.Kc6 which I had first rejected because of 1. ...Rxh7
For such a position, it would be good to indicate "mate in 4", because, as already mentioned, any white move wins.
Not a good one Though.
3/5/2015 - E.Stoddard vs S.Sorenson, corr., 1977
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