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Is there not a shorter mate here? 1.Rg6 Rh6 2.Rxg7 Rxg7 3.Qc8#?
No! After 1 Rg6 Rh6 2 Rxg7? Black is not forced to play 2...Rxg7?? 3 Qc8#! Surprisingly 2...Rh7! overloads Rg7 and simply threatens 3...Rhxg7.a) White cannot play 3 Rxh7 because of 3...Rg1#b) After 3 Rxg8 White loses his queen after 3...Rxd7c) Even 3 Bb8 does not work due to 3...Rhxg7 (or 3...Rgxg7) protecting a7!
By the way 2...Rg6?? does not help Black because of 3 Rxg6! renewing the threat of 4 Qc8#
What's wrong with 1. Bb8?
I was about to ask the same thing!
If you are looking at the two positions (1 Bb8 and 2 Bb8) the difference is that the rook on g8 is protected (1 Bb8) and not protected (2 Bb8).
What allows White in the solution to win the rook (in case of 3...Ra8).With 1 Bb8 Rxb8 2 Rxg7 Ra8 3 Qb7+ Ka5 the win of the rook is not possible.
By the way in your line 1 Bb8 Kb6 2 Rg6 Rh6? 3 Qc7+! mates.
I believe it is no different. If black rook not take Bishop, then mate in 2.Bb8 Kb6 Qc7+ Ka6 Qa7#. both b5 and c5 squres are covered by white pawn c4 and d4. If rook took bishop,
1. Bb8 RxB8 2. Rxg7 Ra8 3. Qb7# or 2. Rxg7 Qb5 3. Qa7#
so no need first trick.
3 Qb7+ Ka5! it's not mate at all!
Yes you are right. Thanks for analysis. So Rg6 is necessary to loot Rh8 away from bottom line so Q can later take Root at a8.
Neat puzzle. Still took me 8 presses of the 'Restart' button!
2. Rxg7 is better
Certainly not! 2 Rxg7? Rh7! and White is lost! A. Shirov had White! So you can be sure he found the best combination here ... (see post #143)
Thank you for the EXCELLENT puzzle, best one in a while, REALLY had to think... MEOW to ALL!!!
YES, but BLACKS BUSTED!
Kind of hard.
Wow, that was hard!
Genius. Thanks for the great moves.
Can't you take the pawn on g7 with the rook before you move the bishop to b8?
White to move and give an unusual checkmate...
Shirov, Alexei (2450) vs Zhuravliov, Valerij (2460)
1. Bb8? R:b8
Nc3 Qa1+ and draw
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