what about qd4 first and then rxd4 bxb7 winning the rook?

1....Bf6 2....Qh4

hard puzzle I think

If 1. Bf6 then where's the mate on 1...Rh8?

hard night

I originally thought 4. Bd2 was correct as it looks natural because it defends the rook on c1, but then after finding the correct answer I figured out why 4. Be1 is the only correct move.  If 4. Bd2 Qd7!  Then if 5. Bxc6 Qxd2 and black immediately recovers his piece.  If 5. Rxc6 Rd8 which double attacks the bishop on d5 and sets up a skewer on the bishop on d2.  The rook cannot defend d5 due to black's bishop on f8.  If 6. e4 then 6...fe.  It looks like white's best might be 6. Bxf7+ Qxf7, recovering his pawn and leaving material equal.

I'm up it's 2:11 AM

Remember white is a rook down, plus a pawn, in the original position so simply recovering the rook with a bishop pair advantage is not best.

I'm alright to go

Nice puzzle!

If the rook moves instead of 2...Nc6 then 3. Bxb7 wins the queen immediately, unless 2...Rd1+.  Then 3. Rxd1 wins the first rook followed by at least the other rook on the next move.  If 3...Nc6 4. Bxc6 would win at least both rooks and the knight.

If 1. Bxd5 Qxd5 2. Qxe7 Nd7 avoids getting checkmated.

Everybody try...answer soon..

 I have realized what you are thinking and it will never happen for me.

What happened?  The position changed!

ummm... oops? lol thanks for pointing that out!

HAHA I just saw the revision, there was supposed to be a knight on h8 so that 1. ...Rh8 wouldnt be possible, it seems there would be no mate in 2 on with the original position, but that is probably still the line I would take lol

In the revision I think 1. Bf6 can be met by 1...Ng6, holding the critical h4 and f4 squares.  Unless I am missing something, I don't see any mate in two with any first move.  Please correct me if i'm wrong.  Maybe it needs to be revised another time!

?

Hard and solvable.