"Perhaps the problem with %'s only arises when players have to play each other more than once. "
well, that just proves my point. or we should just call them "confuser"
Rick, in ALL tournaments, each player will play each player more than once. However, some tournaments start both of these games at the same time (and I'm guessing (but haven't checked yet) that the % complete would be accurate in these cases) and some tournaments start the 2nd game only after the 1st game is complete (and this is where the bug lives).
yes i know,if you didn't notice i qouted my first statement above(in responce), i was referring to my previous statement :completed games+won (but ongoing games)/#of games=%complete w/c simply means the computer might hve include in its computation the games (won) thats ongoing.
ok. i'll investigate. computers are only as smart as the people who program them and... doh!
See my answer, it has nothing to do with computers, everyone once in a while everyone blames them, including myself,and at times it is how we set up the equation and resolve it .
This is where I am going: 104 games have been played, count them on the result board, player no 1 has completed 12 games etc.., and since one player has withdrew, see the stats box, there is 144 minus 16 games or 128 games to be played by each player.This is 81.25% or rounded off to 81%:
I should have added 104 games played divided by 128 games total to be played equals 81.25% or 81% rounded off.
Which tournament are you looking at?
in this tournament: http://www.chess.com/tournament/cti---introductions
there are [11+10+9+8+7+6+5+4+3+2+1]*2 = 132 games.
something is clearly wrong.
These exercises about calculations are not about computations or other fancy math which I am very familiar with.The one thing I can see is that many people calculate the total number of games to be played and they do omit one of the essential condition of the equation, the exceptions or additionnal restraint or constraint or the other elements in the equation.
I have responded to another post using a certain and proved mathematical basic calculation. Here is another way to calculate and if you ask me I can come up with at least 2 more ways to get the right answer, vector analysis is always handy.
So here we go: There are 264 games to play minus the player that withdrew 22 games leaves us with 242 games to play.
Since 116 games have been played which is 242 divided by is 47.9%.
Now one player has quit and 1/12 is 8.33%, but sinbce there are 11 players left his impact on the result is 1 divided by 11 or 9.1%.
Result is 47.9% of games played plus the impact of player that has quit 9.1% equals exactly 57%.
Who are you adressing this to? me Paul or...
we fixed this. the code should be live later this week :)
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