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Maths!

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9th February 2008, 05:27pm
#1
by Darce
Sydney Australia Australia
Member Since: Aug 2007
Member Points: 73

Is anybody here good at calculus? I need to prove the product rule f(x)*g(x)=F(x),

F'(x)=g'(x)*f(x)+f'(x)+g(x), using first principles. Help?


9th February 2008, 05:33pm
#2
by Patzer24
United States
Member Since: Jun 2007
Member Points: 13487
This is a chess site, not a math site. Sadly, all I know is chess.  Embarassed
9th February 2008, 05:37pm
#3
by The_Roses_Thorn
United States
Member Since: Dec 2007
Member Points: 11

Write the derivative of F(x) as the limit as r (or whatever other constant you feel like using) approaches x of (F(r)-f(x))/(r-x).

 This is the same as the limit as r approaches x of (f(r)g(r)-f(x)g(x))/(r-x).

 Note: (f(r)g(r)-f(x)g(x)) can be rewritten as f(x)(g(r)-g(x))-g(r)(f(r)-f(x))

Rewrite your limit using that, and separate it out. You should get the desired result.  


 

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