# Great simple mate in 2!

• 3 years ago · Quote · #1

Can you solve it?

White mates in 2

• 3 years ago · Quote · #2

1Rb7!(2Nb3#) 1...Bxb7 2 Nd7#   1...Be6 2 Nxe6#

• 3 years ago · Quote · #3
Geticus wrote:

1Rb7!(2Nb3#) 1...Bxb7 2 Nd7#   1...Be6 2 Nxe6#

1... Bh3

• 3 years ago · Quote · #4

Bc7 i think...

Hmm no he can play Rb8

• 3 years ago · Quote · #5

You are assuming that peple aren't cheating when you say the first part of this, so the second part is either a redundancy or an assumption that people WILL cheat, therefore rendering the first part of the statement useless.

• 3 years ago · Quote · #6

1. Rb7 is correct I think. 1...Bh3 fails to 2. Nb3 mate

• 3 years ago · Quote · #7
fianchetto123 wrote:

You are assuming that peple aren't cheating when you say the first part of this, so the second part is either a redundancy or an assumption that people WILL cheat, therefore rendering the first part of the statement useless.

Spectacular analysis!

• 3 years ago · Quote · #8

yes correct move is Rb7

• 3 years ago · Quote · #9

Yeah, great and "simple"...lol

• 3 years ago · Quote · #10

no only great

• 3 years ago · Quote · #11

agreed

• 3 years ago · Quote · #12

1....Bh3 2 Nb3# ! sir StMichaelD