Try to solve this interesting puzzle made by me yesterday. White to draw. Your comments are welcome!

I'm surprised that I'm the first to comment on this puzzle, I like it. I think it's great. Thanks!!

This is a good puzzle demonstrating the pain of a rook pawn. There are some other drawing variations. 

 

1. Kd2 also draws. 1. ... a1=Q 2. Bxa1 Kxa1 3. Kc1 Ka2 4. Kc2 Ka1 5. Kc1 draw.

 

There are also some variations in the line you gave. On move 3, Kb3 and Kd3 also draw (since white can still play 4. Kc2) and 4. Kc1 is also stalemate.

I would hate to be black on that game.

very nice!

Very nice.  Demonstrates quite nicely the pain of K + P vs. K + P + B endgames.

Thanks everybody! It's my first puzzle with endgame theme! I was very excited to publish it!

 

 Loomis said:"1. Kd2 also draws. 1. ... a1=Q 2. Bxa1 Kxa1 3. Kc1 Ka2 4. Kc2 Ka1 5. Kc1 draw."

Thank you! I saw only 3. Kc2 Ka2 4. Kc1 Kb3... That's why I added pawns at b4 and b5, so black still wins. But I didn't see 3.Kc1!! Sometimes I am blind

 

'There are also some variations in the line you gave. On move 3, Kb3 and Kd3 also draw (since white can still play 4. Kc2) and 4. Kc1 is also stalemate."

I just chose forcing move, trying to make puzzle look better. I'm not professional in creating puzzles, but I'm trying!

Could white try 3. Kb3 to capture the a3 pawn? It would probably result in a draw as well: 3. Kb3 ... K (any) 4. Kxa3 ... Kb1 5. Bf6 (away somewhere). Is it possible for white to win if black promotes (a1=Q) Bxa1 ... Kxa1 following with Kb3? I am not too familiar with end games- triangulation and all that stuff.

Yeah, that's my mistake - too many other draw variants... And I think you are right - white can win. That's why black would play 3...Kxa1 and agree for stalemate.