The 69 position

Give two chess puzzles in the photo.

- In the first puzzle (yellow, left), White just killed a Black piece and now is turn of Black. Before death, victim had performed 69 moves (each capture is also a move).

- In the second puzzle (blue, right), only one Pawn is promoted, only 5 Black pieces were killed. A1 is concealed .Whose turn is unclear now.

a) Prove that White can “always” checkmate Black within 6 moves in the 1st puzzle, and within 9 moves in the 2nd puzzle.

b) Only consider 1st puzzle. Know the 5 following:

- No piece was killed in row 4. There are not "exactly" 2 pieces, which were killed in the same row. (However, more than 3 pieces is possible)

- There is a killer, who is dead now. At his 60th move and 90th move, he killed 2 White pieces.

- 2 bN were killed side by side (maybe adjacent in a row or a column or a diagonal), but none of them dead on the same row with bQ.  Before death, both bN had never stood at D8 or E8.

- The piece, who killed bQ is still alive.

- 2 pieces, who killed bB, move 6m+9 times and 6n-9 times (m counts the move of wP-A2, n counts the move of wP-D2, at the present).  Know that 1 of 2 killer above is standing next to only 1 other piece.

Please tell me exactly: which piece is the killer, and which piece is his victim (with their name and original location), where is the killer now?

For example: wP-B2 x bN-G8 at A4, killer is at A5. Or bQ x wP-F2 at F6, killer is dead...

https://www.dropbox.com/s/y4o2qx9z7fctm3d/69%20chess.jpg?dl=1

Please seek professional help.

He did, but solving chess problems just doesn't pay what it used to. :P

very hard

Oh you people with your weird puzzles and your asses hanging out. Please pull your pants up.

That was epic.

Two problems presented together while they shouldn't be.

Problem 2

(11+11) The content of a1 is unknown (might be empty or occupied by a unit of either side). One pawn was promoted; White made 5 captures. White to move, mate in 9.

Problem 1

(14+9) White has just made a capture, Black to move.

a. White mates in 6. (Remember that Black starts.)

b. The following information is given; reconstruct all captures (original position of capturer, original position of captured, the square where the capture happened, and the current square of the capturer if exists):

• There was no capture in rank 4.
• There were never exactly two captures in any rank.
• Some Black unit, on its 60th and 90th move (of the piece, not of Black), captured a White unit each. This Black unit has been captured.
• The squares where Black knights were captured were adjacent, either orthogonally or diagonally.
• Black queen wasn't captured on the same row of either Black knight.
• No Black knight has visited d8 or e8.
• The unit that captured Black queen is on the board.
• Suppose m and n are the counts of the numbers of moves of White's a-pawn and White's d-pawn respectively. Then the two units that captured Black bishops have moved 6m+9 moves and 6n-9 moves respectively.
• The two units that captured Black bishops are still present. One of these is currently adjacent to exactly one other piece, either orthogonally or diagonally.

Problem 2

Since White made 5 captures and there are 11 visible Black pieces, a1 is not Black. Since White has two queens and there was only one promotion, this promotion was White's and all the remaining White pieces are original, so a1 is not a White piece. It cannot be a White pawn either for obvious reasons, so a1 is empty.

Finding the mate in 9 is left for the reader. I think it's cooked though due to the symmetry and the play pretty unlikely to use the a-file...

For obvious reasons I don't bother with Problem 1. Retro problems can be way more elegant than that.

Thank you very much 

it's seem to no one can solve this puzzle?

Suggestion:

In part a, pay your attention on the symmetry of the pieces. Find the best fisrt move to reduce Black's choices.

in part b, note that the unit that captured Black queen is exactly on the square where bQ were captured.

tl;dr.

i'm so sad...