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The most difficult 2-mover problem I've ever seen!


  • 22 months ago · Quote · #1

    Asorski

    Warning: If you can't solve this problem within a 2-hour period, please stop solving or you will go mad!

                             White mates in 2

  • 22 months ago · Quote · #2

    KeyserSzoze

    1. qb3 after 2 minutes, can t see the following

  • 22 months ago · Quote · #3

    KeyserSzoze

    1 qb3 nc5 2 rxc5#

  • 22 months ago · Quote · #4

    Asorski

    KeyserSzoze wrote:

    1. qb3 after 2 minutes, can t see the following

    1. Qb3 d1=Q!!!

  • 22 months ago · Quote · #5

    KeyserSzoze

    double check from rook and queen

  • 22 months ago · Quote · #6

    waffllemaster

    KeyserSzoze wrote:

    double check from rook and queen

    Yeah, but it's not mate, you have to find a mate in 2 to solve it.

    e.g.
    1.Qb3  d1=Q
    2. Rcd4+ Kc6   or   2.Rc5+ Kxe4

  • 22 months ago · Quote · #7

    Scottrf

    Asorki, are you sure this is correct? It's not the same as the one I solved.

  • 22 months ago · Quote · #8

    rstoledo

    Saw 1.Nf4+ Nxe4 2.Nxe7++

  • 22 months ago · Quote · #9

    Scottrf

    @rstoledo 2... Bxe7

  • 22 months ago · Quote · #10

    Asorski

    Scottrf wrote:

    Asorki, are you sure this is correct? It's not the same as the one I solved.

    Yah. This is slightly different. The original composer's idea will be revealed here.Cool

  • 22 months ago · Quote · #11

    Asorski

    Everybody please keep on solving. I don't want to sleep until this puzzle is solved. It's already 1:40 Am here in the Philippines!

  • 22 months ago · Quote · #12

    renalboy

    What is the point of problems in impossible positions? White has 16 pieces + king + 3 pawns, therefore position could never arise; what possible practical lesson could one learn from this nonsense?

  • 22 months ago · Quote · #13

    Martin0

    KeyserSzoze wrote:

    1 qb3 nc5 2 rxc5#

    I guess that was a big fail as the knight is pinned at b7 and  it isn't mate as black can play 2...Kxe4

    I'm trying to find a solution, but so far no luck. The position can never arise, but still a funny problem Smile

  • 22 months ago · Quote · #14

    Asorski

    renalboy wrote:

    What is the point of problems in impossible positions? White has 16 pieces + king + 3 pawns, therefore position could never arise; what possible practical lesson could one learn from this nonsense?

    The practical lesson here is: How to solve impossible position without the help of an engine!

    Because of the availability of many solving machines (engines), many people now tries to ask the help of computers to solve a particular chess problem.

    The maker of this problem intentionally put more pieces than the usual we've seen on the chessboard. This is to discouraged cheaters and engine users. Only the real solvers are welcome here.

    As I've said this problem is very very difficult!  Solving this will bring a smile to a solver's face. This is not a Problem composing competition. We're just having fun here!

    Now please try to solve it if you want.

    Again, stop solving if you cannot find mate in 2 within 2 hours or you will go mad!

  • 22 months ago · Quote · #15

    Geticus

    Analizand  pozitia observ:albul are 20 piese:1K;2Q(+1);4R(+2);4N(+2); 6B( din care:2B black(+1) si 4B white(+3) +3 pawns =20 pieces; prin promotie puteau rezulta +5 figures nu 9 !!!de unde inca 4? Apoi negrul are pioni dubli pe coloanele : f (f3;f4)  h(h3;h6) si b5;d2;e7 =7 pawns dar inaceasta structura trebuie sa aiba loc cel putin 4 capturi de piese albe!!!intrebarea este catepiese are albul? 16 sau 24? CONCLUZIA: POZITIE ILEGALA!!!

  • 22 months ago · Quote · #16

    Martin0

    1.Re5+ Nxe5 2.Nxf4#, but unfortunality no mate after 1.Re5+ Kxc4 Frown

  • 22 months ago · Quote · #17

    Asorski

    Geticus wrote:

    Analizand  pozitia observ:albul are 20 piese:1K;2Q(+1);4R(+2);4N(+2); 6B( din care:2B black(+1) si 4B white(+3) +3 pawns =20 pieces; prin promotie puteau rezulta +5 figures nu 9 !!!de unde inca 4? Apoi negrul are pioni dubli pe coloanele : f (f3;f4)  h(h3;h6) si b5;d2;e7 =7 pawns dar inaceasta structura trebuie sa aiba loc cel putin 4 capturi de piese albe!!!intrebarea este catepiese are albul? 16 sau 24? CONCLUZIA: POZITIE ILEGALA!!!

    Thanks for the observation Geticus. You share common sentiment with renalboy. For the explanation please read my post # 15.

  • 22 months ago · Quote · #18

    C-nack

    Nb6 Rd4# (rook from e4, dunno how to note it)?

  • 22 months ago · Quote · #19

    Asorski

    Cnacnel wrote:

    Nb6 Rd4 (rook from e4, dunno how to note it)?

    Then Black king can escape at either c6 or e6. Please try again.

  • 22 months ago · Quote · #20

    Asorski

    I wonder who can solve this very very difficult puzzle.Cool

    Don't use an engine please. Let's have fun!

    Here again is the diagram:

                              White mates in 2


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