I wonder who can solve this very very difficult puzzle.

Don't use an engine please. Let's have fun!

Here again is the diagram:

                          White mates in 2

Nf4 + Nxf4 2. Nxe7#?

Your King is in check!

Please try again.

There's a bishop waiting to take a knight on e7...

Move one:

Ask your opponent if that is a rabbit behind his seat.

Move two:

Remove your King from  the board while sneezing.

White wins irregardless of move(s)

Seriously though, nice position to post.

La problemele de sah ,,ortodoxe" cu sah in 2;3;4;.......n mutari se cere

1 Cheie (prima mutare) UNICA !    Cele cu 2,3 .....solutii se considera DEFECTE! Se admit mai multe soluti la problemele cu ,,mat ajutor" si la cele ,,ortodoxe"  cu  mai mult de  4x dar numai daca autorul indica ASTA,existenta de mai multe solutii si trebuie sa mentioneze cate!

2 POZITIE LEGALA (Rezultata  dintr-o partida chiar imaginara) ;ori la problema dvs. aceasta regula nu se respecta! albul are pe tabla peste 16 piese !!!iar pozitia pionilor negrii putea rezulta dupa inca cateva capturi, am calculat eu 4 deci 20 piese existente +4 capturate rezulta 24 !translate pls ROUMAIN LANGUAGE  FOLOSING! Merci mister ASORSKI  [Sper ca era o problema ,,ortodoxa"  nu heterodoxa sau ,,ferica" ?]

He can't escape c6 but yeah, e6 is legit ^^

Would be nice if it was on a board on which u can move pieces.

Ugh, I keep seeing mate in 3's.

That is a fine defense Scootrf.

Keep trying.

This is not a joke. I hope somebody hit the solution ASAP.

Keep trying dude! Keep trying.

I think I see it! Is it f=Q!, (if NxQ then Re5) if not Qd8#!

Or am I missing something? :D

Geticus, I don't understand your words.

Anyone please translate in english language what Geticus is saying?

Ne7+  Nxe7 2. Nf4#

1. f8=Q?? Black simply plays ...bxc4!!

1.Rc7 black can only move the knight at g6, the bishop at a3, pawn at b5 and Kxe4. If he moves knight 2.Nxf4#, if he moves pawn Rc5#. If he moves bishop to other than b4 or d6 then 2.Rc5# If Bb4 2.Nxb4# If Bd6 2.Nb6#. If Kxe4 2.Nb4#

1. Nxe7+ Bxe7!!

Please try again.

DM_CaptainObvious wrote:

I think I see it! Is it f=Q!, (if NxQ then Re5) if not Qd8#! Or am I missing something? :D

1...bxc4

If bxc4, Rc5 is illegal.

He can't play bxc4 if the rook isn't there.