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The most difficult 2-mover problem I've ever seen!


  • 2 years ago · Quote · #21

    TasmanianTiger

    Nf4 + Nxf4 2. Nxe7#?

  • 2 years ago · Quote · #22

    Asorski

    TasmanianTiger wrote:

    Nf4 + Nxf4 2. Nxe7#?

    Your King is in check!Cool

    Please try again.

  • 2 years ago · Quote · #23

    Scottrf

    There's a bishop waiting to take a knight on e7...

  • 2 years ago · Quote · #24

    PortlandPatzer

    Move one:

    Ask your opponent if that is a rabbit behind his seat.

    Move two:

    Remove your King from  the board while sneezing.

    White wins irregardless of move(s) Cool

    Seriously though, nice position to post.

  • 2 years ago · Quote · #25

    Geticus

    La problemele de sah ,,ortodoxe" cu sah in 2;3;4;.......n mutari se cere

    1 Cheie (prima mutare) UNICA !    Cele cu 2,3 .....solutii se considera DEFECTE! Se admit mai multe soluti la problemele cu ,,mat ajutor" si la cele ,,ortodoxe"  cu  mai mult de  4x dar numai daca autorul indica ASTA,existenta de mai multe solutii si trebuie sa mentioneze cate!

    2 POZITIE LEGALA (Rezultata  dintr-o partida chiar imaginara) ;ori la problema dvs. aceasta regula nu se respecta! albul are pe tabla peste 16 piese !!!iar pozitia pionilor negrii putea rezulta dupa inca cateva capturi, am calculat eu 4 deci 20 piese existente +4 capturate rezulta 24 !translate pls ROUMAIN LANGUAGE  FOLOSING! Merci mister ASORSKI  [Sper ca era o problema ,,ortodoxa"  nu heterodoxa sau ,,ferica" ?]

  • 2 years ago · Quote · #26

    C-nack

    Asorski wrote:
    Cnacnel wrote:

    Nb6 Rd4 (rook from e4, dunno how to note it)?

    Then Black king can escape at either c6 or e6. Please try again.

    He can't escape c6 but yeah, e6 is legit ^^

    Would be nice if it was on a board on which u can move pieces.

  • 2 years ago · Quote · #27

    DM_CaptainObvious

    Ugh, I keep seeing mate in 3's.

  • 2 years ago · Quote · #28

    Asorski

    Scottrf wrote:

    There's a bishop waiting to take a knight on e7...

    That is a fine defense Scootrf.

    Keep trying.Cool

  • 2 years ago · Quote · #29

    Asorski

    PortlandPatzer wrote:

    Move one:

    Ask your opponent if that is a rabbit behind his seat.

    Move two:

    Remove your King from  the board while sneezing.

    White wins irregardless of move(s)

    Seriously though, nice position to post.

    This is not a joke. I hope somebody hit the solution ASAP.

    Keep trying dude! Keep trying.

  • 2 years ago · Quote · #30

    DM_CaptainObvious

    I think I see it! Is it f=Q!, (if NxQ then Re5) if not Qd8#!

    Or am I missing something? :D

  • 2 years ago · Quote · #31

    Asorski

    Geticus wrote:

    La problemele de sah ,,ortodoxe" cu sah in 2;3;4;.......n mutari se cere

    1 Cheie (prima mutare) UNICA !    Cele cu 2,3 .....solutii se considera DEFECTE! Se admit mai multe soluti la problemele cu ,,mat ajutor" si la cele ,,ortodoxe"  cu  mai mult de  4x dar numai daca autorul indica ASTA,existenta de mai multe solutii si trebuie sa mentioneze cate!

    2 POZITIE LEGALA (Rezultata  dintr-o partida chiar imaginara) ;ori la problema dvs. aceasta regula nu se respecta! albul are pe tabla peste 16 piese !!!iar pozitia pionilor negrii putea rezulta dupa inca cateva capturi, am calculat eu 4 deci 20 piese existente +4 capturate rezulta 24 !translate pls ROUMAIN LANGUAGE  FOLOSING! Merci mister ASORSKI  [Sper ca era o problema ,,ortodoxa"  nu heterodoxa sau ,,ferica" ?]

    Geticus, I don't understand your words.

    Anyone please translate in english language what Geticus is saying?

  • 2 years ago · Quote · #32

    DalaiLuke

    Ne7+  Nxe7 2. Nf4#

  • 2 years ago · Quote · #33

    Asorski

    DM_CaptainObvious wrote:

    I think I see it! Is it f=Q!, (if NxQ then Re5) if not Qd8#!

    Or am I missing something? :D

    1. f8=Q?? Black simply plays ...bxc4!!

  • 2 years ago · Quote · #34

    Martin0

    1.Rc7 black can only move the knight at g6, the bishop at a3, pawn at b5 and Kxe4. If he moves knight 2.Nxf4#, if he moves pawn Rc5#. If he moves bishop to other than b4 or d6 then 2.Rc5# If Bb4 2.Nxb4# If Bd6 2.Nb6#. If Kxe4 2.Nb4#

  • 2 years ago · Quote · #35

    Asorski

    DalaiLuke wrote:

    Ne7+  Nxe7 2. Nf4#

    1. Nxe7+ Bxe7!!Cool

    Please try again.

  • 2 years ago · Quote · #36

    Scottrf

    DM_CaptainObvious wrote:

    I think I see it! Is it f=Q!, (if NxQ then Re5) if not Qd8#! Or am I missing something? :D

    1...bxc4

  • 2 years ago · Quote · #37

    Jadeite

    Martin0 wrote:

    1.Rc7 black can only move the knight at g6, the bishop at a3, pawn at b5 and Kxe4. If he moves knight 2.Nxf4#, if he moves pawn Rc5#. If he moves bishop to other than b4 or d6 then 2.Rc5# If Bb4 2.Nxb4# If Bd6 2.Nb6#. If Kxe4 2.Nb4#

    If bxc4, Rc5 is illegal.

  • 2 years ago · Quote · #38

    Asorski

    [COMMENT DELETED]
  • 2 years ago · Quote · #39

    Scottrf

    He can't play bxc4 if the rook isn't there.

  • 2 years ago · Quote · #40

    Martin0

    Jadeite wrote:
    Martin0 wrote:

    1.Rc7 black can only move the knight at g6, the bishop at a3, pawn at b5 and Kxe4. If he moves knight 2.Nxf4#, if he moves pawn Rc5#. If he moves bishop to other than b4 or d6 then 2.Rc5# If Bb4 2.Nxb4# If Bd6 2.Nb6#. If Kxe4 2.Nb4#

    If bxc4, Rc5 is illegal.

    1.Rc7 b4 (bxc5 in illegal) 2.Rc5#


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