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chessman_calum
I know its not directly associated with astronomy but is there a trick to factorising the quadratic:
ax(to the power of four) + bx³ + cx² + dx + e
My actual problem is: z^4 + 2z^3 - 4z^2 - 2z + 3.
All help appreaciated! :)
aspen101
why do you want to factorys the qudrant ?
A nother question why do you wan't to add e?
i was solving some big equation!
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