10573 Players currently online!
Man vs. Machine - good luck!
Turn-based games at any time!
Vote for the best move to win!
Do you have what it takes?
Sharpen your tactical vision!
Get advice and game insights!
Learn from top players & pros!
View millions of master games!
Your virtual chess coach!
Perfect your opening moves!
Test your skills vs. computer!
Find the right private coach!
Can you solve it each day?
Bring it all together!
Beginners, start here!
Make friends & play team games!
News from the world of chess!
Search all Chess.com members!
Find local clubs & events!
Who's the best of your friends?
Read what members are saying!
8 views |
"Mathematics" Great display by you.
cliffordhardin67 comment reminded me of I learned to draw a line with lengh square root of 3 + square root of 5 in 7th grade in Tehran.
Animations are very interesting.
So funny dude ^_^
The only proof I ever remember is using this:http://www.google.co.uk/imgres?um=1&hl=en&safe=off&sa=G&biw=1280&bih=899&tbm=isch&tbnid=WIfwtRNBNrWMxM:&imgrefurl=http://www.btinternet.com/~se16/hgb/pyth.htm&docid=od3z7ilHvN_GqM&imgurl=http://www.btinternet.com/~se16/hgb/pyth2.gif&w=200&h=200&ei=DSocUKq-DcOU0QXduIGQBA&zoom=1&iact=hc&vpx=759&vpy=507&dur=407&hovh=143&hovw=143&tx=96&ty=69&sig=108506534432355335658&page=1&tbnh=143&tbnw=143&start=0&ndsp=24&ved=1t:429,r:21,s:0,i:192 Then the total area if equal to the sum of individual areas, i.e:(a + b)^2 = 4/2(a * b) + c^2= a^2 + b^2 + 2ab = 2ab + c^2= a^2 + b^2 = c^2
ipse qui solvit problema evedat puella.
Hey cliffhardin...come on!!..Who doesn't know that!?..I was tooling with Fermat's Theorem when I was six!..Then! I discovered the Wiggles!..haha hey so well..Google Fabio Lanzoni images. I think he's you dad!
this is very-very nice
True : a squared + b squared = c squared,,,but lets not forget the end .the square root of c squared thereof which is the most common and final mistake of this theorum !!! for instance : lets say a= 2 b=2
then: 2 squared =4 + again 2 squared =4 which = 8 squared=64
the square root of 64 = 8 which is the square root thereof ! Many people forget this last sequence ! the hypotenuse couldnt be 64 ----- it would have to be 8 !!!
Hey Avrilmai, no I don't know that guy. Who is he?
There is a proof of the pythagorean theorem using similar triangles.
who is he?
Hey so well. Have you ever heard of a guy named Fabio?.
About the first picture - it is correct only when a=3, b=4 and the angle between them is 90. In all other values for "a" and "b" this picture is misleading.
just ina pauzzle nisan,in ghazie moheme fisaghorese hamon ke mige dar ye mosalase ghayemol zaviye andaze morabae vatar barabar ast ba majmow morabae 2 zelee digar
Very nice! Napolean Bonaparte came up with a new (at the time) proof, but I cannot recall now which one he got, or if it is one of the ones you showed above.
Create a Photo Album
4 hours ago
9 hours ago
14 hours ago
Why Join | Chess Topics |
Help & Support |
© 2014 Chess.com
• Chess - English
We are working hard to make Chess.com available in over 70 languages. Check back over the year as we develop the technology to add more, and we will try our best to notify you when your language is ready for translating!