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12 views |
"Mathematics" Great display by you.
cliffordhardin67 comment reminded me of I learned to draw a line with lengh square root of 3 + square root of 5 in 7th grade in Tehran.
Animations are very interesting.
So funny dude ^_^
The only proof I ever remember is using this:http://www.google.co.uk/imgres?um=1&hl=en&safe=off&sa=G&biw=1280&bih=899&tbm=isch&tbnid=WIfwtRNBNrWMxM:&imgrefurl=http://www.btinternet.com/~se16/hgb/pyth.htm&docid=od3z7ilHvN_GqM&imgurl=http://www.btinternet.com/~se16/hgb/pyth2.gif&w=200&h=200&ei=DSocUKq-DcOU0QXduIGQBA&zoom=1&iact=hc&vpx=759&vpy=507&dur=407&hovh=143&hovw=143&tx=96&ty=69&sig=108506534432355335658&page=1&tbnh=143&tbnw=143&start=0&ndsp=24&ved=1t:429,r:21,s:0,i:192 Then the total area if equal to the sum of individual areas, i.e:(a + b)^2 = 4/2(a * b) + c^2= a^2 + b^2 + 2ab = 2ab + c^2= a^2 + b^2 = c^2
ipse qui solvit problema evedat puella.
Hey cliffhardin...come on!!..Who doesn't know that!?..I was tooling with Fermat's Theorem when I was six!..Then! I discovered the Wiggles!..haha hey so well..Google Fabio Lanzoni images. I think he's you dad!
this is very-very nice
True : a squared + b squared = c squared,,,but lets not forget the end .the square root of c squared thereof which is the most common and final mistake of this theorum !!! for instance : lets say a= 2 b=2
then: 2 squared =4 + again 2 squared =4 which = 8 squared=64
the square root of 64 = 8 which is the square root thereof ! Many people forget this last sequence ! the hypotenuse couldnt be 64 ----- it would have to be 8 !!!
There is a proof of the pythagorean theorem using similar triangles.
who is he?
Hey so well. Have you ever heard of a guy named Fabio?.
just ina pauzzle nisan,in ghazie moheme fisaghorese hamon ke mige dar ye mosalase ghayemol zaviye andaze morabae vatar barabar ast ba majmow morabae 2 zelee digar
Very nice! Napolean Bonaparte came up with a new (at the time) proof, but I cannot recall now which one he got, or if it is one of the ones you showed above.
just hal mikoni?
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