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Problem ID: 0043722
what if the opponent promotes to a rook ?
Then it's just a draw: it's impossible to force a win with rook and knight versus rook unless the weaker side is already in a very bad position (which isn't the case here).
I was greedy with 1.Rg5, which intends Ra5 and Ra1#. Black can however play d2 and White loses.
interesting is that even after 1..Nf5?? (allowing Re1#) 2.Rxe4?? d2 it is still a draw: 3.Re2! d2-d1=Q 4,Rh2+ Kg1 Rh1+! =
I bother to mention this variation with two redicilous moves because there is sa similar study where both variations are possible for black,making this one...boring/irrelevant.
what if white plays 1.Rg2. I thought it was mate after Ra2 and Ra1# I couldn't find a way for black to stop it
after 1..e4 2.Rg2?? it is quite easy to see that 2..e3 3. Ra2 Kg1 (only move but also winning) cannot be a mate or a win for white. What that was more interesting for me was to see how black wins from that position (otherwise Re3 would not be the only solution) :
4. Kg3 Nf5+ 5.Kf3 (other moves,for examples Kf4 would lose simply to e2 followed by d2 [Ra1+ Kf2]) and now.... (to be continued)
you're right YoniKer. Thanks
2. e1+ does not work because Black can capture and promote to a Rook leaving White's King free to move.
in case of 2.Re1+?,promoting to a knight will work as well...
this problem should be changed.
this problem should be extended! instead of queening, Black has the try ...Nf5, after which White has to find Rg4!
You are outright wrong-after Nf5 white has both Rg4?! (with the idea of Rg1+! and no matter how black captures it is a stalement) AND Re2 with the idea d2-d1=Q(Only try otherwise RxP) Rh2+ and Rh1+.
So after Nf5 there is a double solution-impossible to extend this problem. Do you agree now? :)
Kasparov has beaten Judit in R+N vs R. I think there might be some way to try and play that for win even here.. Problem is it would perhaps take more than 50 moves?!
It was thought before that R+B vs R is nearly always a draw and nowadays? You can see plenty of GM games with R+B vs R where "stronger" side succeeds!
Q has to take R to get out of chk: therefore stalemate. Other pathways result in new Q winning.
R+B v R is more difficult to hold than R+N v R. That being said, even GMs lose R v R+N on rare occasions against other GMs. So it's not completely trivial.
I tried to win like a spaniel.
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