Just For Fun: Series of numbers

This is a new game of counting to a million. The reason why is that here's how to count:

Put your number into the function 2y=x(x + 1)/where x is any positive integer and y is the outcome. What you do when continueing the count is to take the previous outcome and subsitute it for x. x however may not equal 0 or 1. We therefore start at x=2. For example:

Me: 2(2 + 1)/2=3

falling-upwards: 3(3 + 1)/2 = 6

BigOto: 6(6 + 1)/2 =21

What this function actually does is add x and all the integers between x and 0. If x=3, then it is 1 + 2 + 3=6 and if x=4, then 1 + 2 + 3 + 4 = 10. When commenting however please use the function y=x(x + 1)/2.

The goal is to reach a series above a million. After that we go for a billion. Let me start out here: (And also please do not try to predict when by solving the equation. It spoils the fun).

2(2 + 1)/2=3.

No double-posts unless posting comments that aren't part of the count.

You must count up as described by this post. Mess-ups bring it back to x=2.

I have had algebra 1 but not algebra 2, so I can't really do this.

BigOto this utilizes a quadratic function, y=x(x + 1)/2 or y=[(x squared) + x]/2. Try it. You just need to prove why the function works. Try. "If it at first you don't succeed, try, try again."

yay calculus!

y=x(x+1)/2

x=21

y=(21^2 +21)/2

y=(441+21)/2

y=231

isn't that like factorial?  with ! :D

haha erik would ban us if he knew we're wasting his server spaces like tis 

wrong, you had to start with the 3 I gave. Now we start back with x=2.

2(2 + 1)/2=3

i thought that since you already showed those, i should go straight to what happened next

Come on, continue the count.

falling-upwards I was only using you as an example.

It was never specified in the terms of usage.

Continue the count.