FREE - In Google Play
FREE - in Win Phone Store
Got stuck on the 4th move.
but figured it out eventually.
see you tomorrow!
Another nice one.
Nice puzzle,had to hit help at move two 1.Nc6+...Kb6 2.Na5...pxc6 3.Rb7...KxNa5 4.pc3...Rc8,at this polnt I would have exspected Rd8,to cover the winning move, 5.Bd2.I think black could have stopped mate,but know how game would have went had that happened.I hope someone annalyzed puzzle to see what if's.Thank's Chess.Com,for puzzle which was not as easy as ussual.Good day chess heads!!
nice but quite easy just good for refreshing
pretty good and a perfect use and sacrifice of some pieces 2 mate...
Want more chess puzzles? Want a tactics rating?Check out the Tactics Trainer and 10,000+ tactical puzzles!
checkmate in 6
what if black bishop takes the b pawn - then it is not mate in 5
How on earth does a 2000-rated player ask this question?
That is an extremely good question - he's currently rated 2082. Chess.com, please take note.
1. Knight to A5 is still mate in 5 or less moves... can someone help me and point out the flaw in that line thx
third move by black should be to C5, instead to take 2nd knight on A5...holds 1 more move for black, after sacrificing bishop on the sqare b3...;) 4.) Rd1/Bb3 5.) axb/ xy 6.) b4 matt
at least everyone is not saying that it was easy I would love to get into the mindset of someone that moves their pieces in that way
It took a couple of tries and I finally got it.
[COMMENT DELETED BY ADMINISTRATOR THAT CONTAINS SHAMELESS STATEMENT IN THE PAST]
Want more chess puzzles? Want a tactics rating? Check out the Tactics Trainer and 10,000+ tactical puzzles!
the fourth move is debateable but it's a good checkmate.
I was thinking the same thing. And does anyone know why 4.a4 is wrong please? I don't see how both mate threats (b4/Bd2) can be defended.
Probably a bad puzzle. Once there was another puzzle with checkmate along a diagonal and it wouldn't work if you sac the queen for checkmate (which it definitely was on the e8-h5 diagonal) but it worked is you sacced the bishop. a4 should do the same job as b3 in my opinion.
4.a4 is met by 4...Ba2. Then both 5.b4+ and 5.Bd2+ can be met by 5...Kxa4 and it's no longer Mate in 5 as specified.