2/18/2014 - Mate in 3

  • #181
    Bryan681972 wrote:
    chessplayerwholays wrote:

    Qxc6 works as well

    Stopped by 1...Bf5.

    then 2. Rxf5 if pawn takes the rook then Qg6 mate, if instead of pawn takes, and the rook takes the Queen then Rf8+ and then rook on f1 to f7 will follow and is also checkmate. So I think that Qxc6 is still winning unless i missed something.

  • #182

    cool use of sacrafice

  • #183

    well done

  • #184
    Bigmack235 wrote:
    Bryan681972 wrote:
    chessplayerwholays wrote:

    Qxc6 works as well

    Stopped by 1...Bf5.

    then 2. Rxf5 if pawn takes the rook then Qg6 mate, if instead of pawn takes, and the rook takes the Queen then Rf8+ and then rook on f1 to f7 will follow and is also checkmate. So I think that Qxc6 is still winning unless i missed something.

    Oh yes, 1. Qxc6 Bf5 is still winning for white.  1...Bf5 stops white from reaching the puzzle goal of mate in three though, as it will be a mate in four.

  • #185
    [COMMENT DELETED]
  • #186

    Yawwwwwwwwwwwwwwwwwwwwn

  • #187
    [COMMENT DELETED]
  • #188
    [COMMENT DELETED]
  • #189

    good one indeed.

  • #190

    Laugh my f'n assss off @ the top comment

  • #191

    None of  the above

  • #192

    Someone did post before the puzzle... I wonder how you do that, and why do people care so much about being on first page?

  • #193

    Forced mate in 3 !

  • #194

    wow!!! nice sacrifice!!!! GG

  • #195

    nice mate. what about QxQ? id RxQ the you Rf8 hes forced into a mate. If in stead of RxQ the Bxf1 to sav mate but u end up going down a queen for a bishop. Bxf1 Qxc8 Kxf7 QxRh8. Its a thought to consider. Am i correct in my analysis?

  • #196

    Qxc6 also a mate in 3

  • #197

    1.Qxc6 Rxc6 2.Rf8+ Kg7/kh7 3.R1f7#

    or

    1.Qxc6 Rd8 2.Rf8+ Rxf8 3.Qg6#

  • #198

    Puzzle very interesting.

  • #199
    [COMMENT DELETED]
  • #200
    striker153 wrote:

    nice mate. what about QxQ? id RxQ the you Rf8 hes forced into a mate. If in stead of RxQ the Bxf1 to sav mate but u end up going down a queen for a bishop. Bxf1 Qxc8 Kxf7 QxRh8. Its a thought to consider. Am i correct in my analysis?

    If 1. Qxc6 Bxf1 then white has 2. Qxg6#.

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