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# 9/14/2017 - An Abstract Way To Equalize

• #21
aHorseWithNoName wrote:

Come to my intelligent forum

2+2=5 can it be true?

Let a + b = c
Note that 5a - 4a = a
Note that 5a - (2 + 2)a = a

Then 5a - (2 + 2)a + 5b - (2 + 2)b = 5c - (2 + 2)c
Rearranging,

5a + 5b - 5c = (2 + 2)a + (2 + 2)b - (2 + 2)c

Factorising,

5(a + b - c) = (2 + 2)(a + b - c)
Cancelling the common factor (a + b - c), and removing the brackets as they are now redundant,

5 = 2 + 2

Hope this helps.

• #22

• #23

impressively at real

• #24

Wonderful concept.

John 8:21

• #25
fatalphenom wrote:

As a newer player, I find no matter what this ending in a stalemate.

I am certainly no expert myself, but a stalemate? I was thinking more in the lines of a draw? But I might be mistaken

• #26

I don't get the point of that result

Clearly White could Checkmate Black.

• #27

Cool!

• #28

Good one

• #29

The first move has to be a queen check because all other moves lead to instant mate.  There are only four queen checks.  Consider each one.  Narrowing it down like this helps a lot.

• #30

Draw

• #31

That white King looks very vulnerable and my Queen can only give check but do I wish to loose the Queen?.   It might be a light bulb for me. but not just yet.   King to g5 comes to mind as a breather but alas "incorrect"

• #32

Why doesn't white start off with Qe3?

• #33

NİCE ONE

• #34
Gil-Gandel wrote:
aHorseWithNoName wrote:

Come to my intelligent forum

2+2=5 can it be true?

Let a + b = c
Note that 5a - 4a = a
Note that 5a - (2 + 2)a = a

Then 5a - (2 + 2)a + 5b - (2 + 2)b = 5c - (2 + 2)c
Rearranging,

5a + 5b - 5c = (2 + 2)a + (2 + 2)b - (2 + 2)c

Factorising,

5(a + b - c) = (2 + 2)(a + b - c)
Cancelling the common factor (a + b - c), and removing the brackets as they are now redundant,

5 = 2 + 2

Hope this helps.

The fallacy is that if a+b=c, then a+b-c=0, so when you write

"Factorising,

5(a + b - c) = (2 + 2)(a + b - c)"

what you are really saying is that 5 x 0 = (2+2) x 0, which is true, but you can't cancel the 0s to leave 5 = 2+2 because 5x0/0 does not equal 5 and (2+2)x0/0 does not equal (2+2).

This took about the same amount of time for me to solve as the chess puzzle.

• #35

e3 is covered by the Rook on b3.   @marco_lapegna_29

• #36
Grey_Goose wrote:

That white Queen looks very vulnerable and my Queen can only give check but do I wish to loose the Queen?.   It might be a light bulb for me. but not just yet.   King to g5 comes to mind as a breather but alas "incorrect"

Kg5 Qxg4#.  Don't forget which way his pawns are going .

• #37

A very good puzzles for starters but not for me it only made me do some ramdon moves to do it

• #38

I'm late today

• #39

@dsf001  I see now Kg5 is big blunder.   Many Thx.

• #40

Hello and good morning. That was practice puzzle par excellence [pardon my bad French)!

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