Wonderful concept.

John 8:21

fatalphenom wrote:

As a newer player, I find no matter what this ending in a stalemate.

I am certainly no expert myself, but a stalemate? I was thinking more in the lines of a draw? But I might be mistaken

The first move has to be a queen check because all other moves lead to instant mate. There are only four queen checks. Consider each one. Narrowing it down like this helps a lot.

That white King looks very vulnerable and my Queen can only give check but do I wish to loose the Queen?. It might be a light bulb for me. but not just yet. King to g5 comes to mind as a breather but alas "incorrect"

Gil-Gandel wrote:

aHorseWithNoName wrote:

Come to my intelligent forum

2+2=5 can it be true?Let a + b = c

Note that 5a - 4a = a

Note that 5a - (2 + 2)a = a

Then 5a - (2 + 2)a + 5b - (2 + 2)b = 5c - (2 + 2)c

Rearranging,

5a + 5b - 5c = (2 + 2)a + (2 + 2)b - (2 + 2)c

Factorising,

5(a + b - c) = (2 + 2)(a + b - c)

Cancelling the common factor (a + b - c), and removing the brackets as they are now redundant,

5 = 2 + 2

Hope this helps.

The fallacy is that if a+b=c, then a+b-c=0, so when you write

"Factorising,

5(a + b - c) = (2 + 2)(a + b - c)"

what you are really saying is that 5 x 0 = (2+2) x 0, which is true, but you can't cancel the 0s to leave 5 = 2+2 because 5x0/0 does not equal 5 and (2+2)x0/0 does not equal (2+2).

This took about the same amount of time for me to solve as the chess puzzle.

impressively at real