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Not a bad puzzle!
Abstract, indeed. Page 4, woohoo!
yeah, this will end in stalemate
you still dont win
I tried and I tried until what felt like the last legal move came to me finally was the right move. (I could not find the right move because I was looking for check)
I solve it.
September 14th is Cream-Filled Doughnut Day.
Miam! I'll take a dozen, please!....
As a newer player, I find no matter what this ending in a stalemate.
I'm also a newer player, but here there are multiple ways to lose. The idea is to avoid what appears to be a losing position. Congratulations on finding the drawn even position. (unlikely to be stalemated) / I managed (w/ no input errors) the draw as well!
Nothing about this puzzle is abstract in any way.
Come to my intelligent forum
Let a + b = cNote that 5a - 4a = aNote that 5a - (2 + 2)a = a
Then 5a - (2 + 2)a + 5b - (2 + 2)b = 5c - (2 + 2)cRearranging,
5a + 5b - 5c = (2 + 2)a + (2 + 2)b - (2 + 2)c
5(a + b - c) = (2 + 2)(a + b - c)Cancelling the common factor (a + b - c), and removing the brackets as they are now redundant,
5 = 2 + 2
Hope this helps.
The fallacy is that if a+b=c, then a+b-c=0, so when you write
5(a + b - c) = (2 + 2)(a + b - c)"
what you are really saying is that 5 x 0 = (2+2) x 0, which is true, but you can't cancel the 0s to leave 5 = 2+2 because 5x0/0 does not equal 5 and (2+2)x0/0 does not equal (2+2).
This took about the same amount of time for me to solve as the chess puzzle.
Correct, 10/10, your turn to clean the whiteboard.
I had to google abstract too, came up with this - 'abstract as a verb' - 2.extract or remove (something):