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Let a + b = cNote that 5a - 4a = aNote that 5a - (2 + 2)a = a
Then 5a - (2 + 2)a + 5b - (2 + 2)b = 5c - (2 + 2)cRearranging,
5a + 5b - 5c = (2 + 2)a + (2 + 2)b - (2 + 2)c
5(a + b - c) = (2 + 2)(a + b - c)Cancelling the common factor (a + b - c), and removing the brackets as they are now redundant,
5 = 2 + 2
Hope this helps.
The fallacy is that if a+b=c, then a+b-c=0, so when you write
5(a + b - c) = (2 + 2)(a + b - c)"
what you are really saying is that 5 x 0 = (2+2) x 0, which is true, but you can't cancel the 0s to leave 5 = 2+2 because 5x0/0 does not equal 5 and (2+2)x0/0 does not equal (2+2).
This took about the same amount of time for me to solve as the chess puzzle.
instead of trying to bring new math rules that don't exist, just come to my forum and learn
That is an abstract way to equalise.
ur rating is 719. that is way abstract
Here's another proof that 2+2=5:
US$2. + US $2. = CAN $5.!
And it's true
It is worth noting that after Qxe6+, the king MUST take the queen or else the queen takes the rook!
Cancelling the common factor (a + b - c), and removing the brackets as they are now redundant
Less sneaky is 5x=4x
cancel the x and you get 5=4
Good misdirection, I approve.
not related to today's position... still no English translation of Andre Cheron; how is this possible?
Aye, already noted though - comment #52.
very smart move ....
Nothing about this puzzle is abstract in any way.
I had to google abstract too, came up with this - 'abstract as a verb' - 2.extract or remove (something):
had to be a sacrifice
14 Hours ; Alice I am going to send you to the moon.
공부하다 = 배우다 basic math yes we do ♻️♻️♻️
fantastic today's problem !!!
I learned this in my freshman year of high school.
In any triangle, ∠1+∠2+∠3 = 90 degrees.
∠4 is complementary to ∠3.
∠1+∠2+∠3 = 90
∠3+∠4 = 90
∠1+∠2+∠3 = ∠3 +∠4
So, in an informal manner of speaking, 1 + 2 = 4.
I am the 100th commenter.