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mashanator: There are 8 missing units, 2 of them are the bishops. That leaves 6 for c7 to go to g1. Why did you discard one for g1 but later count it again?
Haha. Now that was a stupid oversight.
I should really just read this thread...
numbers one and two definitely (for 1, black wasn't on the 8h side, and as of 2, the knight moved forward and backward).
Three is defintiely possible using the white knights to kill the black ones and then just have the rook move over one square and then back at the end.
Four is almost possible, but black would only be able to move his/her pawns at the end, destryoing the situation.
#1430, problem 1. I'm not sure whether this is correct...
White made 8 promotions (all to rook). Promoting the pawns from a,b,g,h files requires at least 6 captures (axbxa/c, bxa/c, hxgxf, gxf), the exact missing number of Black's units. Thus White's c,d,e,f pawns marched straight. This also implies Black made cross captures to let c,f pawns through (cxd to let White's c-pawn to promote, and then dxc to replace a pawn back to c-file; likewise with fxe and exf). But then d,e pawns are blocked; Black has already used up all 4 captures, and at no time did d- and e-files were empty of Black pawns, so White couldn't promote the central two pawns. So the position is illegal.
#1430 (1) is legal.
Yes, black made 2 sets of cross captures c/d and e/f. There is a way to let all 4 white pawns straight through.
Without checking #1430...
Yes that is legal. I trust Remellion.
...oh crap, really, did I just forget the trick? (White's d-pawn goes to d6; Black captures c6xd5; White's c-pawn marches straight; Black captures d7xc6; White's d-pawn marches straight as well.)
This is what I ment, I got a Roook at h2
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