wait a sec.
Post Your Puzzles.
it happens. Can you proof me that it is impossible :)?
I can.
To get 6 pawns on a file, we need to make a minimum of 9 captures, and this minimum is achievable only for the c,d,e or f files. Each capture needs to be made towards the file where we're assembling the pawn-row.
If we want to make a pawn-row for each player, then those captures need to consist of all the pieces (except the king) plus two pawns.
The problem here is that the rook's pawns (a and h pawns) are pretty useless:
(1) We can use at most one of them in the pawn row itself (they're too far apart to use both).
(2) We can't capture either of them when we're bulding the opposing pawn-row (because that would take the opposing pawn in the wrong direction).
So we don't have enough (non rook's) pawns - we need 6 pawns (of which at most one can be a rook's pawn) for our White pawn row and 2 (neither of which can be rook's pawns) to capture when assembling the Black pawn row.
That's a total of 7 non-rook's pawns, and we only have 6.

By the way, can I ask how that's legal?
Yes it is legal. Since no one got the answer, let me show you. Remember, all i asked was how that position happened after black's 4th move. BTW, this is just a composition.

It is possible (shown in my last comment) due the fact that White's and Black's not so usefull h and a pawns can promote! I DID IT!!!!!
It is possible (shown in my last comment) due the fact that White's and Black's not so usefull h and a pawns can promote! I DID IT!!!!!
Congratulations! I was mistaken.

ALWAYS REMEMBER IT WAS JUHANI HALONEN WHO SHOWED YOU THIS FIRST!!!!
Finland. You could be the next Unto Heinonen. :)
I'd have to use a supercomputer. Can you prove that it is possible?