I would try c4, Qxd2, Bxd2, b6 to support the knight. Now Bc3, Ne3 and c4 may win the knight...
b4 nc4 qe2 if b4 qxd2 nxd2
It was my first idea too, but Qxd2 is not forced, I think they can play ...b6/...b5 giving the knight b7 square.
Qe2 can be answered with Nd6