Just solved it! 
Createsure Feetsure #3
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Dec 27, 2019
0
#4
ATTENTION: This problem requires nothing more than knowing how to multiply and divide, yet no one has made any attempt to solve it (or at least hasn't said that they have). So... I would like to offer 1 pi to the first person than can explain HOW you would go about solving it (with sufficient detail), and 2 pi to anyone who does solve it. READY? SET.... GO!!!
Jan 31, 2020
0
#5
Nobody seems to have attempted this one, so here is a big clue as to getting started:
Anything divisible by 8 is also divisible by 4 and by 2, and anything divisible by 9 is also divisible by 3.
This means that among the three correct numbers (that are all divisible by 11), at least one of them has to also be divisible by 9, 8, 7, 6, and 5. Next, make a list of all the three-digit numbers that are divisible 11. Cross out all the numbers that use the same digit twice. I suggest a spreadsheet, though this list is not as large as you might expect. More help available if requested.
I have written down three 3-figure numbers, that between them use nine different digits. Among these numbers there is at least one that is divisible by 2; at least one that is divisible by 3; at least one that is divisible by 4; at least one that is divisible by 5; at least one that is divisible by 6; at least one that is divisible by 7, at least one that is divisible by 8; at least one that is divisible by 9.
Furthermore, all three numbers are divisible by 11. What are they?