Factorising.

I know its not directly associated with astronomy but is there a trick to factorising the quadratic:

ax(to the power of four) + bx³ + cx² + dx + e

My actual problem is: z^4 + 2z^3 - 4z^2 - 2z + 3.

All help appreaciated! :)

why do you want to factorys the qudrant ?

A nother question why do you wan't to add e?

i was solving some big equation!

Try:  (Z-1) * (Z-1) * (Z+1) * (Z+3)  The terms must be of form  (Z+n);  because the coefficient of Z**4 is 1 and there is the term 3, also a+b+c+d = 2 and  a*b*c*d = 3. The other two terms must also be correct and they are. Had "e" been zero, the problem pretty well falls apart.  That is a,b,c or d must be zero.