Geometric discussion

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Jomsup

He from US.

Jomsup

Jomsup

√3a²/4 = √3

a² = 4

a = 2

Jomsup
Veritasium0 wrote:
JomsupVora2020 wrote:

He from US.

🤣

He once told me that.

I just saw @thecosmos000 use India flag on profile and I'm not sure this is him or not.

Jomsup

Ok just a minutes.

Jomsup

Problem 7:

□ABCD has ∠A = ∠C = 90° and AB=7, BC=15, DA=24.

Find the lenght of CD.

Jomsup
Veritasium0 wrote:

20

Correct!

Jomsup

Problem 8:

ΔABC is a triangle. D, E are points on BC, AC respectively such that AB=AD and EC=ED. If ∠ADE=65° and ∠DEC=90° Find the size of ∠BAC.

Jomsup

Problem 9:

Given a triangle whose 3 adjacent angle on the line of interior are 4x, 5x, and 6x.

Find the value of x.

Jomsup

Problem 10:

ΔABC is a triangle. D,G are points on AB such that AD=DG=GB and E,F are points on AC such that AE=EF=FC. if the area of ​​□DEFG is 30 cm².

Find the area of ΔABC.

Jomsup
Veritasium0 wrote:

65°

Correct!

∠ECD=∠EDC=45°

∠ABD=∠ADC=180°-45°-65°=70°

∠BAC =180°-∠ABC-∠ACB=180°-45°-70°= 65°

Jomsup

Sorry, I just fixed some error of the image in problem no 10.

Jomsup

AD:AG = AE:EF = 1:2

∠DAE = ∠GAF (joint angle)

So ΔADE ~ ΔAGF

In the same way we can prove that ΔADE ~ ΔABC

Then the area ratio of two similar triangles is equal to the square of the side length ratio.

NonVisSummaFortitudinis

What is the probability that the triangle formed by 3 points taken at random on a circle contain the circle's center?

Lincoy3304

1/4

Lincoy3304

Or 1/2

NonVisSummaFortitudinis
Lincoy3304 wrote:

1/4

👌

Lincoy3304

3b1b is cool. There’s no way I can prove it lol, but it’s just awesome

RabishKiReport

Haha

TheCosmos000

True