Number theory discussion

8888÷9 = 987+(5/9)

From "...Which is commonly written as 9| a+16+d"

a+16+b = 27 ; a+b = 11

So max a×b = 5×6 = 30

Problem 11:

Find the smallest positive integer that is divided by 3, 4, 5 and leaves a remainder of 2, 3, 4, respectively.

So x ≡ 2 (mod. 3) x ≡ 3 (mod.4), x≡4v(mod.5)

This means x= 3k +2.

So 3k+2≡3(mod4)

=>3k≡1 (mod4)

=> -k ≡1 (mod.4)

The answer is 59 but I cant work the proof