It's either Rxe1 or Nxg6, I think.
ADK
No one worked it out yet ? geez I'll just have to provide the first answer for you and let see if you can work out the rest.
1.Nxd7# (remove N from h8 & p from f7 ) 11 more to go, happy hunting !
Right, here is the start
here is the first answer-1.Nxd7# (remove N from h8 & p from f7 ) 11 more to go!
2nd answer-Nxg6# (remove Nh4 & Ng6}
3rd answer- gxf4# (remove p g3 & p f4)
4th f4# (remove p f3)
5. f4# (remove p f2 )
6.Rxf5# (remove R f1 & N f5)
7.cxd4# (remove p c3 & p d4)
8.d4# (remove p d3)
9.d4# (remove p d2)
10.Bf4# (remove B c1)
11.Rxe1# (remove R a1 & R e1)
and finally !! Qe4# !!
This was found by David Ellis chess editor for The West Australia.
"Something rather different and perhaps more in keeping with the festive season, an problem by Thomas Dawson with mate in one, not once but 12 times with the stipulation that after each mate you remove the mating piece and any opposing piece that has been captured. For example if you played 1.Rxe1+(not a movein the solution as it isn't mate -1...Ne3)you would remove the white rook that stand on f1 and the black rook standing on e1 and then find a new mate.You may need to set up your board to solve this."
Does everyone understand this? I only understand half of it.