List of all members ranked by ELO and other statistics

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AllanJones

Hello everybody !

I'm new at chess.com [well, in fact I registered last year but I haven't use it seriously until now] and I wondered how I could get a list of all members ranked by ELO, and some statistics about distribution of ELO among members [like average, percentile or even better a histogram].

I tried in the "share/members" menu but I can just see the newly registered and a few other criterias but not ALL members.

Thanks in advance for your help.

ps: I'm now "platinium" so I think I should have full access.

AllanJones

Yes, sure. It's simply because I'd like to know more about members. What is the average ELO. To get an interesting statistic about other members. To know if I'm in the bottom 5% or 10% or the bottom 1%. I'd also like to know what are the top players on this site. Who they are, what's their ranking. And so on ...

Anything wrong with that ? 

May I ask why you would even ask ? :-)

PS: I'm not platinium, I'm Diamond :-) forgot it :-)

AllanJones

Hi again !

BTW, I might have found some of the information I'm looking for [but not all !]. This is in the stats menu, see copy-paste here below. I can get the percentile [18.5%] and some other stats but not all, particularly on the top part of the rating scale.

So if you know how to get more info, please tell me :-)

Live Chess - Blitz

Current: 822
Today's Rank: #1,360,188 of 1,668,777
Percentile: 18.5%
Glicko RD: 51
Highest: 1309 (Dec 22, 2009)
Lowest: 748 (Jul 4, 2014)
Avg. Opp.: 866.962
Best Win: 1182 (XXXXXX)
chrka

Go to the form of playing you are interested in (online, live &c) and choose "View Players" (eg. for online chess). Hope this is what you're looking for.

JGambit
[COMMENT DELETED]
AllanJones
chrka wrote:

Go to the form of playing you are interested in (online, live &c) and choose "View Players" (eg. for online chess). Hope this is what you're looking for.

Many thanks ! This is exactly what I was looking for :-) Even better than my best dreams :-) 

Very nice density function BTW, perfect !

Thanks again !

Allan.