8 queens

Think you have 8 queens . leave these queens to the chess bord that none of theme check other queens .

nobody coulde solve this problem ???

I can only place seven queens in this manner are you sure it can be done? Is there only one solution or many ? The key must be to place them knight's moves apart.

a2, b4, c6, d8, e1, f3, g5, h7, imo

Edit:  Oops, lol that doesn't even begin to work.  I only checked the diagonals in one direction...

Im sure that there is one way but not sure that there is just one way .

thank you very much

There are either 92 or 94 distinct solutions (I forget which - I programmed this a few years ago). Of course, a bunch of those are just rotations or mirror images of each other, so there are fewer than 94 "kernel" solutions.  If yant want the full dump I can look them up.

Well I'm quite amazed at the fund of knowledge on this site you put me in the shade.

It was 92 - divisible by 4. I knew this would come in handy one day Let me know if you find any mistakes!

:: h1 d2 a3 c4 f5 b6 g7 e8
:: h1 c2 a3 f4 b5 e6 g7 d8
:: h1 b2 e3 c4 a5 g6 d7 f8
:: h1 b2 d3 a4 g5 e6 c7 f8
:: g1 e2 c3 a4 f5 h6 b7 d8
:: g1 d2 b3 h4 f5 a6 c7 e8
:: g1 d2 b3 e4 h5 a6 c7 f8
:: g1 c2 h3 b4 e5 a6 f7 d8
:: g1 c2 a3 f4 h5 e6 b7 d8
:: g1 b2 f3 c4 a5 d6 h7 e8
:: g1 b2 d3 a4 h5 e6 c7 f8
:: g1 a2 c3 h4 f5 d6 b7 e8
:: f1 h2 b3 d4 a5 g6 e7 c8
:: f1 d2 g3 a4 h5 b6 e7 c8
:: f1 d2 g3 a4 c5 e6 b7 h8
:: f1 d2 b3 h4 e5 g6 a7 c8
:: f1 d2 a3 e4 h5 b6 g7 c8
:: f1 c2 g3 d4 a5 h6 b7 e8
:: f1 c2 g3 b4 h5 e6 a7 d8
:: f1 c2 g3 b4 d5 h6 a7 e8
:: f1 c2 e3 h4 a5 d6 b7 g8
:: f1 c2 e3 g4 a5 d6 b7 h8
:: f1 c2 a3 h4 e5 b6 d7 g8
:: f1 c2 a3 h4 d5 b6 g7 e8
:: f1 c2 a3 g4 e5 h6 b7 d8
:: f1 b2 g3 a4 d5 h6 e7 c8
:: f1 b2 g3 a4 c5 e6 h7 d8
:: f1 a2 e3 b4 h5 c6 g7 d8
:: e1 h2 d3 a4 g5 b6 f7 c8
:: e1 h2 d3 a4 c5 f6 b7 g8
:: e1 g2 d3 a4 c5 h6 f7 b8
:: e1 g2 b3 f4 c5 a6 h7 d8
:: e1 g2 b3 f4 c5 a6 d7 h8
:: e1 g2 b3 d4 h5 a6 c7 f8
:: e1 g2 a3 d4 b5 h6 f7 c8
:: e1 g2 a3 c4 h5 f6 d7 b8
:: e1 c2 h3 d4 g5 a6 f7 b8
:: e1 c2 a3 g4 b5 h6 f7 d8
:: e1 c2 a3 f4 h5 b6 d7 g8
:: e1 b2 h3 a4 d5 g6 c7 f8
:: e1 b2 f3 a4 g5 d6 h7 c8
:: e1 b2 d3 g4 c5 h6 f7 a8
:: e1 b2 d3 f4 h5 c6 a7 g8
:: e1 a2 h3 f4 c5 g6 b7 d8
:: e1 a2 h3 d4 b5 g6 c7 f8
:: e1 a2 d3 f4 h5 b6 g7 c8
:: d1 h2 e3 c4 a5 g6 b7 f8
:: d1 h2 a3 e4 g5 b6 f7 c8
:: d1 h2 a3 c4 f5 b6 g7 e8
:: d1 g2 e3 c4 a5 f6 h7 b8
:: d1 g2 e3 b4 f5 a6 c7 h8
:: d1 g2 c3 h4 b5 e6 a7 f8
:: d1 g2 a3 h4 e5 b6 f7 c8
:: d1 f2 h3 c4 a5 g6 e7 b8
:: d1 f2 h3 b4 g5 a6 c7 e8
:: d1 f2 a3 e4 b5 h6 c7 g8
:: d1 b2 h3 f4 a5 c6 e7 g8
:: d1 b2 h3 e4 g5 a6 c7 f8
:: d1 b2 g3 e4 a5 h6 f7 c8
:: d1 b2 g3 c4 f5 h6 e7 a8
:: d1 b2 g3 c4 f5 h6 a7 e8
:: d1 b2 e3 h4 f5 a6 c7 g8
:: d1 a2 e3 h4 f5 c6 g7 b8
:: d1 a2 e3 h4 b5 g6 c7 f8
:: c1 h2 d3 g4 a5 f6 b7 e8
:: c1 g2 b3 h4 f5 d6 a7 e8
:: c1 g2 b3 h4 e5 a6 d7 f8
:: c1 f2 h3 b4 d5 a6 g7 e8
:: c1 f2 h3 a4 e5 g6 b7 d8
:: c1 f2 h3 a4 d5 g6 e7 b8
:: c1 f2 d3 b4 h5 e6 g7 a8
:: c1 f2 d3 a4 h5 e6 g7 b8
:: c1 f2 b3 g4 e5 a6 h7 d8
:: c1 f2 b3 g4 a5 d6 h7 e8
:: c1 f2 b3 e4 h5 a6 g7 d8
:: c1 e2 h3 d4 a5 g6 b7 f8
:: c1 e2 g3 a4 d5 b6 h7 f8
:: c1 e2 b3 h4 f5 d6 g7 a8
:: c1 e2 b3 h4 a5 g6 d7 f8
:: c1 a2 g3 e4 h5 b6 d7 f8
:: b1 h2 f3 a4 c5 e6 g7 d8
:: b1 g2 e3 h4 a5 d6 f7 c8
:: b1 g2 c3 f4 h5 e6 a7 d8
:: b1 f2 h3 c4 a5 d6 g7 e8
:: b1 f2 a3 g4 d5 h6 c7 e8
:: b1 e2 g3 d4 a5 h6 f7 c8
:: b1 e2 g3 a4 c5 h6 f7 d8
:: b1 d2 f3 h4 c5 a6 g7 e8
:: a1 g2 e3 h4 b5 d6 f7 c8
:: a1 g2 d3 f4 h5 b6 e7 c8
:: a1 f2 h3 c4 g5 d6 b7 e8
:: a1 e2 h3 f4 c5 g6 b7 d8

I will tell you the answer

The 8 Queen problem was first suggested in 1848 and solved in 1850.

Interesting enough, Carl Jaenisch, inspired by the 8 Queen problem, proposed the 5 Queen problem in 1862 (same parameters but with 5 Queens instead of 8). It was solved by none other than Sam Loyd in 1876.

interesting

???

What do you mean by ??? ?