Biggest string on algebraic notation

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Conquistador

P-KKt8=Q++

ichabod801

For ep capture, the square the capturing pawn ends on is used, not the square of the captured pawn. So there is still no need for disambiguation.

TheGrobe
Conquiscador wrote:

P-KKt8=Q++


Algebraic.

TheGrobe

The subjective move and position analysis characters (!?, !!, =, +/- etc.) shouldn't be included in the character count either as they're not a part of formal algebraic notation.

Ziryab
AnthonyCG wrote:
ichabod801 wrote:
ivandh wrote:

If you have doubled pawns, you get to indicate which one by rank, giving you a an additional character for a grand total of eight(!!).

d7xe8=Q#


No. If you have doubled pawns on d6 and d7, only the one on d7 can capture at e8, so the rank disambiguation is not needed.


If White had the option of en passant and a normal capture at the same time it might work, but I never liked the idea of noting the starting position of the pawn unless there were two pieces that could capture and even then you could just write e.p.

 

 

Here White has 3 captures. I think writing 2.cxd5 e.p. is needed here to capture with c5 since we might not know which c-pawn White used but 2.c5xd5 e.p. and 2.e4xd5 feels like overkill to me.


cxd6

cxd5

exd5

 

No more than four.

rooperi
Ziryab wrote:

cxd6

cxd5

exd5

 

No more than four.


That's interesting, does the capture really happen on a different square?

I think cxd6 could only be construed as e.p., but cxd5 could be ambiguous. Hmmm.....

TheGrobe

The capture always indicates the square that the capturing pawn ends up on.  As a result there is never a need for disambiguation for any pawn move.