ah yes tygxc, continue misconstruing statistical likelihood and intuitive probability as mathematical fact.
ah yes, continue to make a probability estimate using a "method" literally never used in any academia (why is it never used? because it is literally just BS and makes so many self contradictory fallacious assumptions it's hard to know where to begin).
the simplest error is this: you assume errors are completely independent.
if there is a winning line that requires a 60 ply machine to see, and the players only have 40 ply, both of them are going to miss it.

@14816
"114 games all drawn does mean that the odds against the errors all occurring in pairs is astronomical"
++ If all 114 games are drawn, then all 114 games contain an even number of errors: 0, 2, 4.
The most plausible error distribution is 114-0-0-0-0.
However, a few games with a pair of errors: e.g. 112-0-2-0-0 cannot be excluded.
There can be no substantial number of games with a pair or errors, e.g. 60-0-54-0-0,
because then there would be at least 1 game with 1 unpaired error, i.e. a decisive game.
"odds for all of the errors occuring in pairs in these 114 games is necessarily tiny"
++ Assume game 115 were decisive, no clerical error, or due to illness.
Then odds of 1 error = 1/115. Thus odds of a pair of errors= (1/115)² = 0.008%.
The odds could be slightly more if there is a tendency for errors to come in pairs.
"is it more likely that the winning line found or missed by player 2 in this particular instance?"
++ Player 1 is more likely to make an error than player 2 is to miss the win after it.
The reason is player 2 has 1 ply more information: he knows the move played by player 1,
while player 1 was considering several candidate moves. Player 2 looks 1 ply deeper than player 1 did, even with equal hardware, software, and time per move.
Another issue is the time per move. They have 50 days for 10 moves, but are free to spend it as they see fit. If player spends 2 days on his move, and player 2 spends 10 days on his reply,
then player 2 is more likely to spot the error made by player 1.