Math, no thanks. Chess is stressful enough..
Chess with Maths
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Sorry... I admit... I am wrong... I also think that I made a mistake... Yeah, I agree... The position of White does not disinclude the position of Black... I made a mistake that they exist without other... The truth is, they are with each other all of the time on the board... Thanks!... I know now that both of them are on the board on all configurations of position... Therefore, it is a mistake of doubling... Sorry... Thanks!...
Optimissed wrote:
StockOfHey wrote:
What is life?... Does it sucks or not?... LOL...
I hesitate to imagine why Americans constantly use the idea that if something's bad, that can be described by the metaphor of performing a presumably unnatural sexual act. I hope they grow up one day but I don't think they will.
I like it!... Thanks... 
In how many ways two queens shall be placed into 8×8 chessboard such that they never get cancel by each other ( there are only two queens on board place , assume white plays first ).
I found the words "that they never get cancel by each other". It is hard to get... If you did not combine the definition of the second sentence "assume white plays first", it is hard to know the real definition of the word cancel...
There are two definition:
1. decide or announce that (a planned event) will not take place.
2. (of a factor or circumstance) neutralize or negate the force or effect of (another).
The first one says that, capturing a piece is included in the problem... Because, if you cancel the effects of the other piece, you must capture it while the ones who capture remain hence "they did not cancel each other"...
The second one says that, capturing a piece is not included in the problem... Because, if you capture the other, it will not exist...
Because most of us agreed that the second definition is what we are talking about... I guess, the second definition seems more practical...
Besides, queens are not kings... are not they?
If we also treat them as kings, they are not allowed to capture the other... Is not it?
StockOfHey wrote:
If we also treat them as kings, they are not allowed to capture the other... Is not it?
Well if you read carefully I got the same doubt When I thought about it
But we placed two queens on chessboard note that is assumed to be default case of hypothetical situation without consideration of king
Is it good to paraphrase it this way? "How many possible configuration such that a Queen would not be able to capture the other Queen of opposite color?"
StockOfHey wrote:
In how many ways two queens shall be placed into 8×8 chessboard such that they never get cancel by each other ( there are only two queens on board place , assume white plays first ).
I found the words "that they never get cancel by each other". It is hard to get... If you did not combine the definition of the second sentence "assume white plays first", it is hard to know the real definition of the word cancel...
There are two definition:
1. decide or announce that (a planned event) will not take place.
2. (of a factor or circumstance) neutralize or negate the force or effect of (another).
The first one says that, capturing a piece is included in the problem... Because, if you cancel the effects of the other piece, you must capture it while the ones who capture remain hence "they did not cancel each other"...
The second one says that, capturing a piece is not included in the problem... Because, if you capture the other, it will not exist...
Because most of us agreed that the second definition is what we are talking about... I guess, the second definition seems more practical...
Well as per your question
I have used the word cancel because if I would write capture then definitely some will come up and will say capturing has has only one ways
Also capturing is the choice whether the queens would like to do capture or not
As per your concern I will edit question for less confusions
StockOfHey wrote:
Is it good to paraphrase it this way? "How many possible configuration such that a Queen would not be able to capture the other Queen of opposite color?"
Yes
Thank You for sharing your thoughts... I am glad...
StockOfHey wrote:
Thank You for sharing your thoughts... I am glad...
Thanks to you also . Discussion makes more corrections if there is mistake.
Optimissed đã viết:
There are 42 ways the Qs can be placed with the white Q on a1. There are 42 ways if the white Q is on a4. If the white Q is on f4, there are 38. Logically, for all the edge squares there are 42. If on b7 there are 40, so a pattern is developing. If we divide the board into concentric tracks, the outer track contains squares all of which are 42. The next track inwards 40, the next track inwards, 38.
The final track is the centre four squares. Taking one at random, d4, there are 5x6 +6 = 36
So we have 4x36 + 12x38 + 20x40 + 28x42 = 2576
Double it and we have the answer.
5152
This is (kinda) wrong. The answer is 2576 you dont need to double it heres why
I think the reason you double it is to count the inverse variation of this position. But you already count that before when you considered the 4 square intermost layer queen position. So you dont need to double the answer to count the inverse variation of a position, because its already coumted before Therefore, the answer is 2576.
Dont tell me the problem is not the question its the wording of that question
The fact that i can grab a blue-colored queen from a 4 player chess board and put it in here is even worse
hello😒
Mr_Mathematician đã viết:
StockOfHey wrote:
In how many ways two queens shall be placed into 8×8 chessboard such that they never get cancel by each other ( there are only two queens on board place , assume white plays first ).
I found the words "that they never get cancel by each other". It is hard to get... If you did not combine the definition of the second sentence "assume white plays first", it is hard to know the real definition of the word cancel...
There are two definition:
1. decide or announce that (a planned event) will not take place.
2. (of a factor or circumstance) neutralize or negate the force or effect of (another).
The first one says that, capturing a piece is included in the problem... Because, if you cancel the effects of the other piece, you must capture it while the ones who capture remain hence "they did not cancel each other"...
The second one says that, capturing a piece is not included in the problem... Because, if you capture the other, it will not exist...
Because most of us agreed that the second definition is what we are talking about... I guess, the second definition seems more practical...
Well as per your question
I have used the word cancel because if I would write capture then definitely some will come up and will say capturing has has only one ways
Also capturing is the choice whether the queens would like to do capture or not
As per your concern I will edit question for less confusions
I think you can change the cancel to "in a line of sight" just to be clear and please tell me what queen color is being used in this puzzle
Mar 15, 2024
0
#79
Atharv8849 wrote:
Ashvath23 wrote:
Atharv8849 wrote:
Many people might think what is use of that but in reality software engineer need such calculations
Yes!
Hello ashvath
Nice to meet my all friends after long time
Mar 15, 2024
0
#80
CoDCVN wrote:
Optimissed đã viết:
There are 42 ways the Qs can be placed with the white Q on a1. There are 42 ways if the white Q is on a4. If the white Q is on f4, there are 38. Logically, for all the edge squares there are 42. If on b7 there are 40, so a pattern is developing. If we divide the board into concentric tracks, the outer track contains squares all of which are 42. The next track inwards 40, the next track inwards, 38.
The final track is the centre four squares. Taking one at random, d4, there are 5x6 +6 = 36
So we have 4x36 + 12x38 + 20x40 + 28x42 = 2576
Double it and we have the answer.
5152
This is (kinda) wrong. The answer is 2576 you dont need to double it heres why
I think the reason you double it is to count the inverse variation of this position. But you already count that before when you considered the 4 square intermost layer queen position. So you dont need to double the answer to count the inverse variation of a position, because its already coumted before Therefore, the answer is 2576.
The reason why we need to double the answer because you need to calculate for both the queens . For example, case-1
Case - 2
In this two cases the position of the two queens differ. For this example we can conclude that in one situation there are two possibilities . Like changing the colour of the two queen.
What is life?... Does it sucks or not?... LOL...