Another Problem the Computer Couldn't Solve
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I've solved it. Let me know if you want a hint.
solved it I think.. not sure I agree with the solution though
Hmm.. the only forced mates I see are mate-in-3s such as 1.Bc2 fxe6 2.dxe6 h2 3.Bxh7#. I'll take another look in the morning with fresh eyes.
Jan 19, 2008
0
#5
I see the solution. This has a similiar idea the other problem the computer couldn't solve. The key hint is to think about what was blacks last move. It is possible to find out just by looking at this setup. I can provide the solution if people want me to later. :)
einstein_69101 wrote: I see the solution. This has a similiar idea the other problem the computer couldn't solve. The key hint is to think about what was blacks last move. It is possible to find out just by looking at this setup. I can provide the solution if people want me to later. :)
I'm not sure it's possible to know what Black's last move was by the position alone(unless, of course we know that white has mate in two).
Jan 19, 2008
0
#8
silentfilmstar13 wrote: einstein_69101 wrote: I see the solution. This has a similiar idea the other problem the computer couldn't solve. The key hint is to think about what was blacks last move. It is possible to find out just by looking at this setup. I can provide the solution if people want me to later. :)
I'm not sure it's possible to know what Black's last move was by the position alone(unless, of course we know that white has mate in two).
It is a mate in 2. It is a mate in 2 because we can figure out blacks last move. If we don't think about blacks last move then we won't be able to find a mate in 2. Think about how can all 6 pawns get to the position they are in now. And then think about was there at least 2 different possible moves for black to reach that point. :)
einstein_69101 wrote:silentfilmstar13 wrote:einstein_69101 wrote:I see the solution. This has a similiar idea the other problem the computer couldn't solve. The key hint is to think about what was blacks last move. It is possible to find out just by looking at this setup. I can provide the solution if people want me to later. :)
I'm not sure it's possible to know what Black's last move was by the position alone(unless, of course we know that white has mate in two).
It is a mate in 2. It is a mate in 2 because we can figure out blacks last move. If we don't think about blacks last move then we won't be able to find a mate in 2. Think about how can all 6 pawns get to the position they are in now. And then think about was there at least 2 different possible moves for black to reach that point. :)
still you can't see blacks last move from this position alone so it's like you have to adjust the problem to fit the answer wich I think is a little weird.
i thing !!! ??? I've solved it
Jan 19, 2008
0
#11
Actually on 2nd thought I have it narrowed down to the fact that the black pawn on c5 was moved on the previous turn. I was thinking the pawn moved two spaces because it couldn't of have come from c6 where it would have been attacking the king. If this was the case then I see a mate in 2, but now that I think of it that pawn could have captured diagonally from b6 or d6 on the previous turn. The en passant would not be a valid move in those cases. Using en passant is the only way of mating in 2 that I can see.
Why was h3 not possible on Black's last move?
Jan 19, 2008
0
#13
silentfilmstar13 wrote: Why was h3 not possible on Black's last move?
Since pawns can never move backwards then the pawns on f7 and g7 never moved through out the whole game. How does black have a pawn on h6? It must have been the g7 starting pawn and at one point it captured diagonally to move to h6. Could this have been the previous move? No because white is already occupying the g7 square. What about the black pawn on g5? This has to be the e7 starting pawn because we have already determined the f7, g7, and h7 starting pawns and it is not possible for a black pawn on the d-file to reach g5. And since the white bishop occupies f6 then this pawn did not move on the previous turn. There is a black pawn on h3. This pawn is the d7 starting pawn since the c7 starting pawn would not be able to reach that square. This pawn did not move on the previous turn because the white rook occupies g4. What is left? The black pawn on c5.
Since pawns can never move backwards then the pawns on f7 and g7 never moved through out the whole game. How does black have a pawn on h6? It must have been the g7 starting pawn and at one point it captured diagonally to move to h6. Could this have been the previous move? No because white is already occupying the g7 square. What about the black pawn on g5? This has to be the e7 starting pawn because we have already determined the f7, g7, and h7 starting pawns and it is not possible for a black pawn on the d-file to reach g5. And since the white bishop occupies f6 then this pawn did not move on the previous turn. There is a black pawn on h3. This pawn is the d7 starting pawn since the c7 starting pawn would not be able to reach that square. This pawn did not move on the previous turn because the white rook occupies g4. What is left? The black pawn on c5.
Jan 19, 2008
0
#14
Here's the proper FEN string for this position:
5Nk1/5pPp/4PB1p/1KpP2p1/6R1/1B5p/P7/8 w - c6 0 1
Now computers can solve it as they know it is possible to capture at c6. Notice "c6" indicating en passant square.
5Nk1/5pPp/4PB1p/1KpP2p1/6R1/1B5p/P7/8 w - c6 0 1
Now computers can solve it as they know it is possible to capture at c6. Notice "c6" indicating en passant square.
einstein_69101 wrote: silentfilmstar13 wrote: Why was h3 not possible on Black's last move?
Since pawns can never move backwards then the pawns on f7 and g7 never moved through out the whole game. How does black have a pawn on h6? It must have been the g7 starting pawn and at one point it captured diagonally to move to h6. Could this have been the previous move? No because white is already occupying the g7 square. What about the black pawn on g5? This has to be the e7 starting pawn because we have already determined the f7, g7, and h7 starting pawns and it is not possible for a black pawn on the d-file to reach g5. And since the white bishop occupies f6 then this pawn did not move on the previous turn. There is a black pawn on h3. This pawn is the d7 starting pawn since the c7 starting pawn would not be able to reach that square. This pawn did not move on the previous turn because the white rook occupies g4. What is left? The black pawn on c5.
Since pawns can never move backwards then the pawns on f7 and g7 never moved through out the whole game. How does black have a pawn on h6? It must have been the g7 starting pawn and at one point it captured diagonally to move to h6. Could this have been the previous move? No because white is already occupying the g7 square. What about the black pawn on g5? This has to be the e7 starting pawn because we have already determined the f7, g7, and h7 starting pawns and it is not possible for a black pawn on the d-file to reach g5. And since the white bishop occupies f6 then this pawn did not move on the previous turn. There is a black pawn on h3. This pawn is the d7 starting pawn since the c7 starting pawn would not be able to reach that square. This pawn did not move on the previous turn because the white rook occupies g4. What is left? The black pawn on c5.
I hadn't thought of that. Thanks.
Jan 19, 2008
0
#16
piotr wrote: Here's the proper FEN string for this position:
5Nk1/5pPp/4PB1p/1KpP2p1/6R1/1B5p/P7/8 w - c6 0 1
Now computers can solve it as they know it is possible to capture at c6. Notice "c6" indicating en passant square.
5Nk1/5pPp/4PB1p/1KpP2p1/6R1/1B5p/P7/8 w - c6 0 1
Now computers can solve it as they know it is possible to capture at c6. Notice "c6" indicating en passant square.
I am guessing the FEN string gives the information of the puzzle setup. I am also guessing that you wrote out the FEN string based off of what you saw in the diagram. How do you know that black didn't have bxc5 or dxc5 on the previous turn? We wouldn't be able to use the en passant rule for these cases.
A white pawn on c6 rather than a2 would satisfy this puzzle, then.
Jan 19, 2008
0
#18
donkenmar wrote:
I solved it d6 any exf6 or Bxe6
If 1 d6 then 1...c4 which will delay checkmate by one move. This move blocks the bishop and white is not able to checkmate the black king in one more move.
Jan 19, 2008
0
#19
einstein_69101 wrote:
I am guessing the FEN string gives the information of the puzzle setup. I am also guessing that you wrote out the FEN string based off of what you saw in the diagram. How do you know that black didn't have bxc5 or dxc5 on the previous turn? We wouldn't be able to use the en passant rule for these cases.
It is "Another Problem the Computer Couldn't Solve" and I was only explaining why. The position FEN was just incomplete for computers. But maybe it is just a puzzle prepared for humans to surprise them?
einstein_69101 wrote:silentfilmstar13 wrote:Why was h3 not possible on Black's last move?
Since pawns can never move backwards then the pawns on f7 and g7 never moved through out the whole game. How does black have a pawn on h6? It must have been the g7 starting pawn and at one point it captured diagonally to move to h6. Could this have been the previous move? No because white is already occupying the g7 square. What about the black pawn on g5? This has to be the e7 starting pawn because we have already determined the f7, g7, and h7 starting pawns and it is not possible for a black pawn on the d-file to reach g5. And since the white bishop occupies f6 then this pawn did not move on the previous turn. There is a black pawn on h3. This pawn is the d7 starting pawn since the c7 starting pawn would not be able to reach that square. This pawn did not move on the previous turn because the white rook occupies g4. What is left? The black pawn on c5.
Since pawns can never move backwards then the pawns on f7 and g7 never moved through out the whole game. How does black have a pawn on h6? It must have been the g7 starting pawn and at one point it captured diagonally to move to h6. Could this have been the previous move? No because white is already occupying the g7 square. What about the black pawn on g5? This has to be the e7 starting pawn because we have already determined the f7, g7, and h7 starting pawns and it is not possible for a black pawn on the d-file to reach g5. And since the white bishop occupies f6 then this pawn did not move on the previous turn. There is a black pawn on h3. This pawn is the d7 starting pawn since the c7 starting pawn would not be able to reach that square. This pawn did not move on the previous turn because the white rook occupies g4. What is left? The black pawn on c5.
If I'm not mistaken this doesn't exclude that black moved bxc5 the previous move.
Salam
Let thing with us ... because i don't solve it ...
but please if any Genius solve it don't write the solution now ... give more time to thinking
write only " i solved "
and thanks
White to play and mate in two moves