Beat my puzzle and get lucky
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Falcon14Nerdalcon
Jan 6, 2025
0
#1
Jan 6, 2025
0
#2
The point of this puzzle is to find a Mate in 2. NOT A MATE IN 1. I understand if you found the Mate in 1, but the point is to find Mate in 2. Happy Hunting!
Feb 23, 2025
0
#4
this would be a fun puzzle, but IT’S AN ANALYSIS BOARD! Not a puzzle!!!!!
Where is the mate in one?
So the point is to find mate in 2, but there are more than one solution for even that.
White is missing a dark-squared bishop (DSB), an h-pawn and either a c-pawn or an e-pawn. White promoted a light-squared bishop (LSB).
Black is missing the original DSB (e and g pawns blocked it from ever moving), a knight an a-pawn and an h-pawn. White made one pawn capture (on the d file) and maybe another one (the f8 bishop had to be captured by a piece in its home square). Black made one pawn capture (on the e-file) and could only promote by making it's only available capture with a pawn. White promoted a second LSB on either g8 (pawn capture required), e8 (pawn capture required by the d pawn and then two more by the a and c pawns), c8 (two pawn captures needed by either black or white to get around the c-pawn) or a8 (two pawn captures needed by white). The only option that does not require too many pawn captures is promoting on g8.
One idea is: the Black h-pawn moved to h4, captured white's DSB on g3 and then promoted to a DSB on g1. White's h-pawn then moved to h7 and captured Black's knight on g8, promoting to an LSB. White's e-pawn moved to e5 and was captured. White has no remaining piece that can be captured on b2 so Black is unable to promote another pawn That leaves nothing left that can be captured on d4.
The starting position cannot be reached by legal moves from the standard start and thus is not a valid standard problem (requires a chess960 start to allow Black's DSB the ability to move without needing the e7 or g7 pawns moved).
jetoba wrote:
White is missing a dark-squared bishop (DSB), an h-pawn and either a c-pawn or an e-pawn. White promoted a light-squared bishop (LSB).
Black is missing the original DSB (e and g pawns blocked it from ever moving), a knight an a-pawn and an h-pawn. White made one pawn capture (on the d file) and maybe another one (the f8 bishop had to be captured by a piece in its home square). Black made one pawn capture (on the e-file) and could only promote by making it's only available capture with a pawn. White promoted a second LSB on either g8 (pawn capture required), e8 (pawn capture required by the d pawn and then two more by the a and c pawns), c8 (two pawn captures needed by either black or white to get around the c-pawn) or a8 (two pawn captures needed by white). The only option that does not require too many pawn captures is promoting on g8.
One idea is: the Black h-pawn moved to h4, captured white's DSB on g3 and then promoted to a DSB on g1. White's h-pawn then moved to h7 and captured Black's knight on g8, promoting to an LSB. White's e-pawn moved to e5 and was captured. White has no remaining piece that can be captured on b2 so Black is unable to promote another pawn That leaves nothing left that can be captured on d4.
The starting position cannot be reached by legal moves from the standard start and thus is not a valid standard problem (requires a chess960 start to allow Black's DSB the ability to move without needing the e7 or g7 pawns moved).
Nice retro-analysis.
But it doesn't really matter, right? The f5 bishop can simply be removed, and the g7 or e7 pawn as well. In fact, half of the pieces can be removed and nothing changes.
The real challenge would be to transform this into a real puzzle that has only one solution. I'm not sure it's easy.
magipi wrote:
jetoba wrote:
White is missing a dark-squared bishop (DSB), an h-pawn and either a c-pawn or an e-pawn. White promoted a light-squared bishop (LSB).
Black is missing the original DSB (e and g pawns blocked it from ever moving), a knight an a-pawn and an h-pawn. White made one pawn capture (on the d file) and maybe another one (the f8 bishop had to be captured by a piece in its home square). Black made one pawn capture (on the e-file) and could only promote by making it's only available capture with a pawn. White promoted a second LSB on either g8 (pawn capture required), e8 (pawn capture required by the d pawn and then two more by the a and c pawns), c8 (two pawn captures needed by either black or white to get around the c-pawn) or a8 (two pawn captures needed by white). The only option that does not require too many pawn captures is promoting on g8.
One idea is: the Black h-pawn moved to h4, captured white's DSB on g3 and then promoted to a DSB on g1. White's h-pawn then moved to h7 and captured Black's knight on g8, promoting to an LSB. White's e-pawn moved to e5 and was captured. White has no remaining piece that can be captured on b2 so Black is unable to promote another pawn That leaves nothing left that can be captured on d4.
The starting position cannot be reached by legal moves from the standard start and thus is not a valid standard problem (requires a chess960 start to allow Black's DSB the ability to move without needing the e7 or g7 pawns moved).
Nice retro-analysis.
But it doesn't really matter, right? The f5 bishop can simply be removed, and the g7 or e7 pawn as well. In fact, half of the pieces can be removed and nothing changes.
The real challenge would be to transform this into a real puzzle that has only one solution. I'm not sure it's easy.
Remove e7 (freeing the f8 bishop), e5, f5 (removing the need to promote a bishop) and h3 (uncovering g1). Move f7 to e8 (to block the f7 rook),, d8 to d6 (covering h2 after e5 is cleared), d4 to c3 (blocking out the c4 queen and removing a needed capture).
Now if 1 Ra1+ Kg2 or 1 Rxh2+ Bxh2 or 1 non-check Bxg6# (or Bxg6+ if the non-check was Qxa6 or Bxc6# if there was a capture on c6).
So 1 f4+ any 2 Ra1# (works after both Qg2 and Kg1)