Hello
Only 2 moves to "end", very hard!
Sort:
Oran_perrett wrote:
i still have 7:
1...Qe1#
1...Qb1#
1...Qg2#
1...gxh2+ 2.Kf1 h1=Q#
1...gxh2+ 2.Kf1 h1=R#
1...g2 2.f3 Qe1#
1...Qf3 2. Kf1 Qd1#
And why does white winning not count?
1...gxh2+ 2.Kf1 h1=Q#
1...gxh2+ 2.Kf1 h1=R#
those solutions are only 2 cases of 1...gxh2+ 2.Kf1. So they are the same.
My final way is:
1...Qh1 2.Kh1 g2 3.Kg1 but Black doesn't have any way to go, so no one win
Black go first.
- Show that there are atleast 7 different ways that Black can "finish" this game with maximum 2 moves.
- 2 ways is different if they are able to satisfy 1 of 2 conditions:
+ First moves of Black are different.
+ Same Black first moves. But with any White first move, then Black have 2 methods to deal at his 2nd move.
Example: Qe4-b1