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The Beauty of Miniature Chess Puzzles!

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aurelcablayan

To chaotic_iak:

I am very sure of the position, there is no missing or misplaced man. Mate means checkmate. The term "cooperate" is not appropriate, I am sorry, it is because Black defenses actually focused on frustrating checkmate to White. Black should try as much as possible to avoid giving mate. White on the other hand must find a way or struggle to get mated, some sort of suicide chess!

Uncia_Uncia

Post 38:

1. Rb5 c3 (only move) 2. Rb2+ cxb2# (forced).

That should work. Personally I like selfmates very much.

aurelcablayan

Thank you very much Uncia_Uncia. I love selfmates too but I limit myself to miniatures- maximum number of man is seven.

chaotic_iak

...I forgot pawns can capture, sideways.

When I posted that, I was thinking "how can Black be forced to give mate in two, if he working together with White (an easier problem, of course) can't even give mate in two?". In directmates, it's something like this: "Even if White can move Black's pieces to his own advantage (helpmate), White still can't mate Black in two. How can White mate Black in two if Black defends (directmate)?"

But then I saw Uncia_Uncia's solution and facepalmed. Nice composition!

aurelcablayan

aurelcablayan

This is really fun guys, please solve it without computer aid! Thanks!

chaotic_iak

Dang, if only White can skip his move, Black must mate with 1... axb2#...

My current try is 1. Qc5 Ka4 2. Qd5 c3 3. Qc5 axb2+, but that's not mate. Still searching...

aurelcablayan

You are right chaotic_iak. This problem is so much similar to triangulation in endgame studies. Initially, White has the move. White must waste a move and arrives at the same position with Black to move!

chaotic_iak

Oh, right, check Black on the second move so he's forced to move the king (and not b4-b3). 1. Qc8 Ka4 (axb2# and White wins) 2. Qa6+ Kb3 (forced) 3. Qc6 axb2# (forced).

David210
aurelcablayan

Correct chaotic_iak!

aurelcablayan

Remellion



aurelcablayan

Great Remellion you got it right too!

aurelcablayan

aurelcablayan

This is rather a harder type of selfmate problem than the other selfmate problems previously presented. It is easy to predict that the pawn on c4 delivers the mate on b2, but it is somehow difficult to calculate how it is realized.

Remellion
aurelcablayan

That one is also correct Remellion. But I expected on the 2nd move 2.Qg5! Try it and you'll arrived at the same solution.

Uncia_Uncia
aurelcablayan wrote:

That one is also correct Remellion. But I expected on the 2nd move 2.Qg5! Try it and you'll arrived at the same solution.

But after 2. Qg5 Kc3, there is no solution, as far as I can see.

aurelcablayan

 I see Uncia_Uncia thanks for that. I only considered 2... c3 after 2.Qg5, I didn't notice that the Black King can also go to c3 spoiling the problem completely. Nice analysis Uncia_Uncia, I'll make adjustments to my record on that!