Trang chủ
Chơi
Câu đố
Học
Theo dõi
Tin tức
Cộng đồng
Thêm nữa
Đăng ký
Đăng nhập
Tiếng Việt
Giao diện sáng
Giao diện ban đêm
Hỗ trợ
Đăng ký
Đăng nhập
Cơ sở dữ liệu các ván đấu
Tim R Spanton
Tên đầy đủ
Tim R Spanton
Sinh
Jan 1, 1957
(68 tuổi)
Nơi sinh
Liên đoàn
England
Hồ sơ
Tổng số ván cờ
207
10% Win
16% Draw
74% Loss
Như quân Trắng
98
10% Win
16% Draw
74% Loss
Như quân Đen
109
9%
16% Draw
75% Loss
Tim R Spanton Ván cờ
Các kỳ thủ
Kết quả
Các nước đi
Năm
Tim R Spanton
(1896)
Ole Christian Moen
(2201)
1. e4 e5 2. Nf3 Nc6 3. Bb5 a6
Ruy López Opening: Morphy Defense, Exchange, Alekhine Variation with 7...Bd6
½-½
56
2025
Tim R Spanton
(1896)
Milos Mozny
(2232)
1. e4 c5 2. Nf3 e6 3. c4 d5
Sicilian Defense: Kramnik Variation
0-1
50
2025
Tim R Spanton
(1824)
Jonathan Day
1. e4 c6 2. d4 d5 3. Nc3 dxe4
Caro-Kann Defense: Tartakower Variation
1-0
42
2023
Gabor Glatt
(2220)
Tim R Spanton
(1858)
1. Nf3 d5 2. g3 Nc6 3. d4 Bf5
King's Indian Attack
1-0
37
2023
Tim R Spanton
(1889)
Luke Jones
1. e4 e6 2. d4 d5 3. Nc3 Nf6
French Defense: Main Line, Alekhine-Chatard, Spielmann Variation
1-0
24
2022
Hugh W Murphy
(2203)
Tim R Spanton
(1889)
1. d4 d5 2. Nf3 Nc6 3. e3 Bg4
Queen's Pawn Opening: Zukertort, Chigorin Variation
1-0
57
2022
Tim R Spanton
(1951)
Rohilla Shivika
(1744)
1. e4 e5 2. Nf3 Nc6 3. Bb5 a6
Ruy López Opening: Morphy Defense, Exchange, Alekhine Variation with 7...Bd6
1-0
58
2020
Tim R Spanton
(1951)
Maaike Keetman
(2203)
1. e4 c5 2. Nc3 Nc6 3. Nge2 e5
Closed Sicilian Defense: Chameleon Variation
0-1
31
2020
Daniel GH Gallagher
(2171)
Tim R Spanton
(1951)
1. b3 b6 2. e4 e5 3. Nf3 Nc6
Nimzowitsch-Larsen Attack: Symmetrical Variation
1-0
27
2020
Gwilym Price
(2110)
Tim R Spanton
(1951)
1. e4 c5 2. Nf3 g6 3. d4 cxd4
Sicilian Defense: Open, Accelerated Dragon, Modern Variation
½-½
19
2020
Tim R Spanton
(1951)
Svetlana Sucikova
(2160)
1. e4 c6 2. d4 d5 3. Nc3 dxe4
Caro-Kann Defense: Classical, Spassky, Lobron System
½-½
70
2019
Tim R Spanton
(1951)
Sacha Brozel
(2188)
1. c4 c5 2. Nc3 Nc6 3. g3 g6
English Opening: Fianchetto, Ultra-Symmetrical Line
0-1
30
2019
Nigel R Davies
(2484)
Tim R Spanton
(1900)
1. Nf3 Nc6 2. d4 d5 3. Bf4 Bg4
Queen's Pawn Opening: Zukertort, Chigorin Variation
1-0
28
2019
Tim R Spanton
(1901)
Craig W Pritchett
(2275)
1. Nf3 Nf6 2. c4 e6 3. Nc3 c5
English Opening: Symmetrical, Anti-Benoni Variation
0-1
56
2018
Tim R Spanton
(1927)
David Fitzsimons
(2328)
1. c4 e5 2. Nc3 Nf6 3. Nf3 Nc6
English Opening: Four Knights, Nimzowitsch Variation
0-1
23
2018
Adam Bukojemski
(2222)
Tim R Spanton
(1901)
1. e4 e5 2. Nf3 Nc6 3. Bb5 Nf6
Four Knights Game: Double Spanish Variation
1-0
24
2018
Josef Pribyl
(2250)
Tim R Spanton
(1923)
1. f4 f5 2. Nf3 Nf6 3. b3 b6
Bird's Opening
1-0
68
2018
Claus Pitschka
(2228)
Tim R Spanton
(1943)
1. d4 d5 2. c4 e6 3. Nc3 Nf6
Queen's Gambit Declined: Semi-Tarrasch, Main Line, Exchange Variation
1-0
22
2018
Kumar Sumit
(2219)
Tim R Spanton
(1943)
1. e4 e5 2. Nf3 Nc6 3. Bc4 Bc5
Giuoco Piano Game
1-0
26
2018
Kim Le Quang
(2267)
Tim R Spanton
(1851)
1. c4 c5 2. g3 g6 3. Bg2 Bg7
English Opening: Symmetrical Variation
½-½
40
2018
Tim R Spanton
(1821)
Dr Bernd Baum
(2267)
1. c4 c5 2. Nc3 Nc6 3. g3 g6
English Opening: Fianchetto, Ultra-Symmetrical, Botvinnik System
½-½
41
2017
Jan Bartos
(2209)
Tim R Spanton
(1858)
1. d4 d5 2. c4 e6 3. Nf3 Nf6
Queen's Gambit Declined: Catalan Opening
1-0
13
2017
Sebastian Plischki
(2397)
Tim R Spanton
(1858)
1. c4 c5 2. Nc3 Nc6 3. Nf3 Nf6
English Opening: Fianchetto, Ultra-Symmetrical, Mecking Variation
0-1
46
2017
Tim P Wall
(2236)
Tim R Spanton
(1880)
1. e4 e5 2. Nf3 Nc6 3. Bc4 Bc5
Giuoco Piano Game: Main Line, Giuoco Pianissimo Variation
½-½
33
2017
Tim R Spanton
(1908)
Peter S Poobalasingam
(2243)
1. d4 d6 2. e4 Nf6 3. Nc3 e5
Pirc Defense
½-½
34
2016
Đầu trang
1
2
3
4
5
Các ván đấu
Chọn một cách khai cuộc hay một người chơi để tìm
Cố định màu
Tìm kiếm
Nâng cao
Bình luận gần nhất
Jordi Magem Badals gặp Mikhail Tal, 1992
Thomas E Rendle gặp Aryan Tari, 2025
William J Barrow gặp Bobby Fischer, 2024
Ewa Barwinska gặp Christopher Guzman, 2025
Alan Pichot gặp Alexei Kornev, 2025