Aleph beit gimmel aleph beit gimmel (triplets) #112 Mine. B only. Triplets are another pattern through verse 1. Aleph beit gimmel aleph beit gimmel (triplets) #112 Mine. B only. In the first verse, we take 3 letters at a time, subtract the first two and the last two, and then subtract the two results. We get 1,1,1,4,9,1,11,16,15 and then the last letter is 27. Notice all the 1s and squares of numbers. Also, 11 is a 1 put next to a 1. For the 15 and 27, 27 is 33 and if we switch the 5 and 2, 125 is 53 (25 is 52). For 15-27, 2,5,7,15,17,127,215,217 and 257 are also all one away from numbers that are exponents of small numbers. 512 is an exponent and like above comes from rearranging two digits of 15-27. 15-27 seems to give the maximum amount of these numbers of any four-digit combination. Also we did 1257. Looping the digits around from 7 back 1, the differences are 1,3,2 and 4. These are consecutive integers. They also make pi, so if we have 5217 we get pi or 3.142. 5217 = 3*37*47. 37 is a Star of David number very common in my patterns. 3*47 = 141, giving us 3.141 so we have pi=3.142 and pi=3.141. It is in fact 3.1416.
virtuousabyss29 Mar 14, 2024
https://www.chess.com/club/the-knights-bishops-and-rooks-chess-team
ConnectedComet Nov 30, 2021
Hello! For today, one geometry problem. A square with side lenght 1 has inscribed semicircle. One line starts at the top left corner is tangent to the semicircle, and ends at the side of the square. What is lenght of the line. For solution: https://www.youtube.com/watch?v=sCtN40gp7oM
stupnik_2_0 Mar 19, 2021
Hello! Today, I didn't put question, only one interesting video. https://www.youtube.com/watch?v=KcjGe5a7Lwg
ArtistOfChessDestruction Mar 18, 2021
Hello! Today's puzzle is little harder than yesterday's. If ABC+ABC+ABC=CCC What are A, B and C. (A,B and C are diferent digits. Hard: 3/10 Solution: https://www.youtube.com/watch?v=PwiRVHoA8MA (Ako ne znate engleski, a voljeli biste riješiti ovaj problem napišite za verziju na hrvatskome.) Comment if you solve.
stupnik_2_0 Mar 16, 2021
Hello all! In this club I will write 1 one math riddle, puzzle or question every day/week. Today puzzle: Hard: 3/10 If AA + BB + CC = ABC, what are the values of A, B, and C? All the digits are distinct and positive. Give this problem a try and when you ready watch video for solution: https://www.youtube.com/watch?v=iI0yzWncjH4 You can write down if you solve problem. (Ako ne znate engleski, a voljeli biste riješiti napišite pa ću napisati i na hrvatskome)
ArtistOfChessDestruction Mar 15, 2021
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