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LLLhk

Grade School problem in China, but probably for most of you will be middle school xD:

Pipe A can fill a pool in 2 hours, pipe B can fill it in 1 hour, if pipe C can fill it in x hours, and altogether the pool can be filled in 30 minutes, what is x?

 

 

 

BTSVFan1230

omg china school system and education system is similar to Korea!! we also learn those kind of problems which is mostly about "x"

cellomaster8
BTSVFan1230 wrote:

omg china school system and education system is similar to Korea!! we also learn those kind of problems which is mostly about "x"

Isn't that just algebra

LLLhk
cellomaster8 wrote:
BTSVFan1230 wrote:

omg china school system and education system is similar to Korea!! we also learn those kind of problems which is mostly about "x"

Isn't that just algebra

yeah

BTSVFan1230

whatever XP

LLLhk

so anyone can solve it???

BTSVFan1230

yes and no i knida know but kinda don't XD

cellomaster8

Isn’t it 2

LLLhk

Correct

c124875

My solution:

Pipe A= 1/2 pool/hour

Pipe B= 1 pool/hour

Pipe C= y pool/hour

So in 30 minutes it's :

0.5*0.5+1*0.5+0.5y=1

And just solve y for how much pipe C have fill the pool for 1 hour

(1/4)+(1/2)+(1/2)y=1

3/4+(1/2)y=1

(1/2)y=1/4

y=1/2 pool/hour

Then just search x with velocity equation

x= 1 pool / 1/2 pool/hour

=1*2

=2 hour

Ragnar_Andersson

Yes, and from that result we deduce that Pump A = Pump C => we choose the most cost-effective pump x2.