Chess clock: what is the time-delay mode?

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KIAttack2016

Now I just have read FIDE Laws of Chess 6.3.2.  What is the time-delay mode?  Would you kindly show me a simple explanation, please?

Martin_Stahl

The rule explains itself but a clock with regular delay does not start until the delay time has elapsed on each move.

Rsava

Here is a simple example.

You play a game with the time control 10 min d10 so you both get 10 mins plus a 10 second delay.

When your opponent punches their clock, your timer does not start counting down until 10 seconds later. You make your move and punch your clock in 8 seconds - your clock does not move. 

Your opponent makes their move and punches their clock. Your clock does not start counting down. You take 15 seconds to make your move and punch your clock but only 5 seconds have gone off of your clock.

Does that explain it?

Eyechess

Another way to explain it is that the player's time clock is delayed in starting.  It is delayed by the amount of the set delay time.

Also, if a player does not use all the delay time to make their move and hit their button, they do not get the unused delay time added to their clock.  So, as Rsava pointed out above, the main time clock does not change or move if a person does not use all the time of the delay.  With this, a player can never have more time on his clock than what he started with.

This is different than the increment.  In the increment, the increment time is added to the main clock time.  If the player does not use all the increment time for his move and button hit, then the unused increment time is added to the main time.  With this it is possible for a player to have more time on his clock than he originally started with.

 

Kings_Indian_YK2017

KIAttack2016 の書き込み:

Now I just have read FIDE Laws of Chess 6.3.2.  What is the time-delay mode?  Would you kindly show me a simple explanation, please?

Thank you, everyone! Now I think I understand. If, (T): remaining time (M): my thinking time on move (d): time delay Then, If M<=d (T)=(T) If M>d (T)=(T)-((M)-(d)) Is it correct?

Kings_Indian_YK2017

Kings_Indian_YK2017 の書き込み:

KIAttack2016 の書き込み:

Now I just have read FIDE Laws of Chess 6.3.2.  What is the time-delay mode?  Would you kindly show me a simple explanation, please?

Thank you, everyone! Now I think I understand. If, (T): remaining time (M): my thinking time on move (d): time delay Then, If M<=d (T)=(T) If M>d (T)=(T)-((M)-(d)) Is it correct?

If (M) is smaller than (d ), (T)=(T). If (M) is larger than (d), (T)=(T)-((M)-(d)). ???

Martin_Stahl

Yeah. But the easiest way to think about is that your clock doesn't start until the delay time has elapsed.

 

Unless Bronstein delay is used, in which case it runs and adds back the amount of time used, up to and including the delay, but no more than that.

thesourpop
Kings_Indian_YK2017 wrote:

 

Kings_Indian_YK2017 の書き込み:

 

 

KIAttack2016 の書き込み:

 

Now I just have read FIDE Laws of Chess 6.3.2.  What is the time-delay mode?  Would you kindly show me a simple explanation, please?

 

Thank you, everyone! Now I think I understand. If, (T): remaining time (M): my thinking time on move (d): time delay Then, If Md (T)=(T)-((M)-(d)) Is it correct?

 

 

If (M) is smaller than (d ), (T)=(T). If (M) is larger than (d), (T)=(T)-((M)-(d)). ???

yes thats right 

@kingsindian