How to solve multiple pawn endings like this

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sta202020

black to move

Is there some related theories to recommend?

Toldsted

Black's chance to win rely on wether he can win the d6 pawn. Otherwise it is a draw as none of the Kings can leave the enemys free pawns.

This will require a b7-b6. A White b4 or a5 could be irritation/holding, so first thought should be 1...a5 to stop White's b- and a-pawn from moving. 

Second thought should be wether White can reply with 2.b4 and win a pawn rush: 2...axb4 3.a4. Some calculation (and this is the hard part) will show that this is not the case. The White pawns cannot succed on their own, and the Black b- and h-pawns will win.

So then the plan is clear: 1...a5 and then we move our King to c6 (e6 is probably good enough), play b6 and win the White pawns - and then winning the ending is easy.

And the same way of thinking can be used in other pawn endings. But be aware: the result will always be up to concrete calculations. And it is easy to miscalculate a tempo in your head - and a tempo is often the difference between two results. If I have miscalculated something above, then it just proves this :-)

tygxc

@1
Black wins. It is a matter of calculation. Black must first play 1...a5 to prevent b4-b5 and c6. Then black threatens 2...h5 and 3...g4 himself. So white must break 2 b4 anyway. Then both sides queen, but black stays 3 pawns up, enough to win.

sta202020

thank both of you

zone_chess

a5 is the move indeed. That's a good insight.

Spotting the win in these positions usually starts by seeing that 1. your king has more mobility 2. your king is more centralized and as a result 3. your king will reach the 'free' pawns faster than the opponent can defend.

On top of that you have a free h-runner. If I am calculating correctly, you would already have won this position without the h-pawn. So this is a double win. -10 on the computer evaluation probably.