There is a very nice little game/puzzle in Silman's endgame book. White has his king on c1 and black has his on c8. The objective of the game with the white king is to get to any of the squares f8/g8/h8. If you can manage with white, white wins. If you defend with black, black holds/wins. I've played that game with both colours against friends and won with both colours. You need to count the squares between your king and the other king and time your advances properly. Try it on a board for half an hour and see if you can work it out.
Can u show this with a board diagram & decision offshoots ?....thx in advance .
I do not feel up to the task of indicating "decision offshoots", but I think that perhaps one line is sufficient to indicate the idea.
So white to move here, he can play Kc2 and he apparently has the opposition. Ok, so now imagine the white king on c2, black's turn to now move. Black can play Kf7, and now he has the opposition? So this rule is stupid. Nobody appears to have an opposition that they could possibly maintain. So how can it possibly ever help knowing this failed rule?
After 1. Kc2 Kf7, Black does not have the opposition. The rectangle f7-c7-c2-f2 does not have the four corners of the same colour. ...
"... c7 and f2 are black. ..." - mariners234
"... However c7 and f2 are nothing to do with this entire post lol. …" - sg4rb0
The rule is based on the idea that Black's move, 1...Kf7, so-to-speak, "builds a rectangle" determined by the position of the white king and the new position of the black king. That rectangle has the corners as indicated by peepchuy, "f7-c7-f2-c2". The rule is that one gains the opposition if one makes a move that "builds a rectangle" with all of the corners having the same color. 1...Kf7 does not gain the opposition because f7, c7, f2, and c2 are not all the same color.