Chess 960 openings

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tonymtbird

i think you are worried about the opening to much.  just play smart and don't make tactical mistakes.  It would take 960 books just for one color in one opening per position, is that really what you want?  if you respond "yes" i submit that you have to much free time and need another hobby besides chess..

Streptomicin

Yea, good idea rich, but if I know what moves are best I would have much higher rating in regular chess. I need some GM - engine opening moves, THE best ones there are, not the one I consider such.

Streptomicin

Offtopic, are you a girl rich, or your pic is sister/girlfrend/daughter?

Streptomicin

And the trophy goes to RainbowRising, who also did not see that this was posted in "FUN WITH CHESS" but got it anyway.

kco

LOL to rainbowrising

Streptomicin

All you have posted here is exactly why I love 960 chess. I had many games where <1500 players play 15+ book moves very fast. There is not such thing in 960, you are on your own from move 1. And the best way to use chess principles.

Little-Ninja
Streptomicin wrote:

But how can you learn anything if setup changes every time. I spent years memorizing openings, and I dont even know where to start here...


Learn strategy and positional play and of course tactics better, then u can play any position comfortably. Opening fundamentals still apply even in chess960, it is just u have to adapt it to where the pieces are placed.

Streptomicin

@ Ian_Sinclair

I guess you did not read last 3-4 posts. Undecided

Little-Ninja

Nope hahaha. You think the advice is still less valid for it though?

Apoapsis
phbookworm wrote:

960 seems too large?

I am not mathematician, a kid in school, so i will try to apply my limited knowledge.

Since, white/black are always mirrored, I will jsut concentrate on white.

> For a1, there are exactly six peices, which can be put. (Exclude king, and black bishop)

>> In case, there is a rook on a1, there are exactly five peices which could be placed on b1. (Excluding rook-already placed, other rook-king must in between, and white bishop) .

>> If a1 != rook, then n(b1) = 5. (Exclude king, and white bishop, and peice already placed on a1)

In just these two squares, no of combinations possible: 

>> If a1 == rook, 5

>> If a1!=rook, 5!= 120.

Total = 125.

If you proceed in such a manner, I think, you can arrive at answer, or you can just google chess960 formual, and search for it, I am sure there must eb one lying there.  


 Lets see...

Dark bishop has 4 places...

light bishop has 4 after that... 4x4

The queen has 6 squares after that... 4x4x6

Then the 2 knights have 12 different arrangements after that... 4x4x6x12

The king and rook then just go in the remaining 3 squares, king in the middle...

4x4x6x12x1 comes to... 1,152?

Huh?

kco

look it up at the wiki you got it right xbigboy

ichabod801

There are ten ways to place two knights into five squares, not twelve. That makes 4 x 4 x 6 x 10 = 960.

Apoapsis
ichabod801 wrote:

There are ten ways to place two knights into five squares, not twelve. That makes 4 x 4 x 6 x 10 = 960.


 Whoops... lol :P I was thinking 6 twice Embarassed At least I sorta got it...

phbookworm

Good one xbigboy.

I missed the obvious... and goen into staright away complex.