K+2N Vs K

How I can mate the lonely king with two knights. (K+N+N VS K) What's the basic theory of this end game???

cool:) there is way but u need some luck too

it's a draw, you need at least 1 bishop.

Put another way, it cannot be forced. This means that if you are ever down two Knights and trade everything else off, it's a draw. Stop the clocks and declare a draw. If you're playing online, offer the draw. The interface should recognise the draw and declare it for you. The one thing you should not do is let the clock run out. You will actually lose on time! 

But, if you ever get to a position where it's 2N +K vs K+P, the Knights can often force a win. The method for that is very tricky tho. You have to stop the pawn with one N, drive the K to a corner with the K and other N, then create a stalemate position on your turn. Only then do you let the pawn move and use the blockading N to deliver mate.

Here it is in diagram form:

But If Black has a pawn, the same configuration loses!

Here's a nice, ranked numerical summary, and it's the way I think of such 1-3 -piece endgames:

N+N+N (9 points) - mate exists, forcible, slightly tricky

Q (8 points) - mate exists, forcible, easy

R (5 points) - mate exists, forcible, easy

B+B (6.5 points) - mate exists, forcible, slightly tricky

B+N (6.25 points) - mate exists, forcible, definitely tricky

N+N (6 points) - mate exists, not forcible

B (3.25 points) - no mate exists

N (3 points) - no mate exists

Thanks @ Smysolv