Now let's assume there's a forced win for black.>>
Can you not see that is logically impossible?
Of course it's not logically impossible. It would merely mean that the opening position constitutes zugzwang. ...
It's not too often that I agree with Optimissed's "logic", but here I think he may have a point.
A zugzwang position normally means a board layout where Black has a forced win if it's White to play and White has a forced win if it's Black to play. However the initial board layout with Black to play is illegal, so can it properly be called a zugzwang position?
I don't think that follows. The fact that it isn't Black's move (which I guess is what you mean by "the initial board layout with Black to play is illegal") shouldn't have any bearing on the question of whether, with white to play, black could force a win. I don't see how deductive logic can foreclose the psosibility of this position being zugzwang, any more than it can with any other postition being considered for possible zugzwang.
Of course, just from experience we can say with about 99.99999999999999999999% confidence that the opening position isn't zugzwang. But there's no logical, a priori, reason it can't be. (At least not until we have a 32-piece tablebase.)
Now let's assume there's a forced win for black.>>
Can you not see that is logically impossible?
Of course it's not logically impossible. It would merely mean that the opening position constitutes zugzwang. ...
It's not too often that I agree with Optimissed's "logic", but here I think he may have a point.
A zugzwang position normally means a board layout where Black has a forced win if it's White to play and White has a forced win if it's Black to play. However the initial board layout with Black to play is illegal, so can it properly be called a zugzwang position?