Breaker not Bracket
Tournament Tie-Breakets
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May 6, 2020
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#3
soccerking12345 wrote:
In these Round-Robin Daily Tournaments let's say there are four people in a group and only TWO advance to the next round.
We'll call the players A,B,C, and D. So A beats B twice, B beats C twice, C beats A twice, and each A,B, and C beat D twice. Who advances? A,B, and C are all 4-2 (four wins and two losses), and they're in a three way tiebreaker where the normal head-to-head won't work. Furthermore, They all beat D, so you can't judge based off their other games (because those to were identical).
How can we figure out who advances? Does what happened in previous rounds matter? Does who won their games first matter? How would we know?
Thank you
Only the current round matters and the tiebreak is the sum of the players won against and half of the players drawn against.
In your example all three have the same score and same tiebreak so all three will move to the next round.
https://support.chess.com/article/314-how-do-ties-in-tournaments-work
All three advance even though it was supposed to only be two?
In these Round-Robin Daily Tournaments let's say there are four people in a group and only TWO advance to the next round.
We'll call the players A,B,C, and D. So A beats B twice, B beats C twice, C beats A twice, and each A,B, and C beat D twice. Who advances? A,B, and C are all 4-2 (four wins and two losses), and they're in a three way tiebreaker where the normal head-to-head won't work. Furthermore, They all beat D, so you can't judge based off their other games (because those to were identical).
How can we figure out who advances? Does what happened in previous rounds matter? Does who won their games first matter? How would we know?
Thank you