Another Problem the Computer Couldn't Solve
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That isn't guaranteed mate in two. 1. Bc2 fxe6 2. dxe6 h2 3. Bxh7#
solved it,
piece of cacke
silentfilmstar13 wrote: Why was h3 not possible on Black's last move?
It's possible but it doesn't matter, the mate still happens after black moves his pawn to h3
another one of those easier retro-problems disguised as mate-in-n --- yawn.
There are some real difficult ones of this kind... [of course the computer can solve it if you give it the right fen ;) ] the diagram has the wrong fen - if you click the pgn/fen dropdown box , then THAT fen has no mate-in-2!
Oh piotr has covered that in his post...
i solved it. pretty easy.
I think the solution is similar to that of the problem "mate in one". Don't forget anything "en passant"
solved it fast... This is a sweet mate. Pretty simple, don't know why the computer couldn't solve it.
einstein_69101 wrote: I see the solution. This has a similiar idea the other problem the computer couldn't solve. The key hint is to think about what was blacks last move. It is possible to find out just by looking at this setup. I can provide the solution if people want me to later. :)
I admit, I didn't see it until I saw this comment.
i cant understand??????
All this talk about "en pasant"...
This is another option:
1. Bc2 h2 (1... h5 2. Bxh7#) 2. Bxh7#
Nice and easy