Direct and indirect attacks are both attacking a square.
If two rooks are lined up on a square containing a pawn, you would say you had two pieces defending the pawn, not one direct and one indirect.
My answer was correct, as if both sides have pieces hitting a square, one is attacking it, one is defending ;)
Semantics. I took it to mean both sides, because it's more of a challenge.
It's just as easy however it's phrased.
I just realised something: my position in post #11 is wrong. I have one too many promoted pieces! I have 7 promoted pieces, but I also have two pawns.
So, the most number of pieces from one army that can cover a square is 15.
I just realised something: my position in post #11 is wrong. I have one too many promoted pieces! I have 7 promoted pieces, but I also have two pawns.
So, the most number of pieces from one army that can cover a square is 15.
Everything but one bishop basically. Pretty simple stuff.
You have too many promoted pieces.
How can you have only 2 promoted bishops if 4 are on dark squares?
In the second you have 6 promoted knights and two promoted bishops and a pawn.
Both have too many.
If that were real white would take the Q and black would take a knight or smh and mate real quick.
This is the most peices that can cover a square (one color only) legitimatally.
2 more knights?
Tho the OP hasn't announced any winners, I'm pretty sure the correct answer is 15.
The piece can be any piece from the starting 32, including promoted pieces and kings (as long as the king is the very last piece to take the attacker in case an exchange happens, which would be fun to see haha.) Albeit, it is probably impossible to put the king in such position with the rooks, sincei t would always be under check.
I do apologize! I never took into account pawn promotions!