Mate in two seems impossible

Is there ANY solution in this problem?

White to move and mate in two . . .

EDIT: Founded the solution ^_^

Hi!

something like: 1. Qg7 Rxg1 2. Ke3# ?

I think it works also with 2. Ke7#

bye

Simone

Ng3 followed by Qd8?

If he takes the rook, then the Knight has the only open square e4 coverd, and if he takes the Knight then the rook covers the e4 square.

Just a thought...

I think mate in 3 is the best.

1. Ng3 Nb7 2. Kxb7 Anymovehere 3. Qd8# or Rc5#

The solution is:

1. Rc4 Rxh4 2. Ne3#

Ng3 doesn't work due to e4, and Qg7 doesn't work on exf5, now let's try Qxg5, as before if Rxg any then Ne3 and Ne7 both are mate, If Rxh4, well there is Qg2+ but black can play Re4 or just pawn to e4 before white can finish with the pretty Rc5#, but again that is three moves.  Then the next thing to try would be Rc4 so if the Nxc4 then Qa8# so far so good, how about Rxc4 or Rxh4.  If Rxc4 then Ne3 or Ne7 are mate, and if Rxh4 then Ne3 is mate.  Ok, so two more options, Kxc4 and just e4.  Let's see what happens on Kxc4 it looks like Qxe6 is mate (thank you little black pawns on b4 and d3 keeping black's king from escaping and of course the N is doing a beautiful job of holding c3 while the king is holding the b5 square and that Bg1 is holding off the final escape at c5).  So we have to see what happens on e4.  Well if black plays e4 then the king has only two legal squares d5 and e5 which means that we only have to check and hold those two squares while not allowing black to interpose with a piece and guess what, Rc5 is check and mate.  Ok, so all we have left is pawn moves and the three other knight moves, which checking all one by one, we see that Ne3 is mate in all those cases so we have solved the puzzle.  Answer 1.Rc4

Rxc4 Ne7

q at g5 if rook take the queen then horse at e7.sorry not good with positions thinks

are we allowed to mate in 1?   Nc3#

is white on bottom or top.

cool

Nope, It's from a magazine

i found another way to do it

kc3

check mate